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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.
The unlabelled-to-unlabelled cells of the twelvefold way
Statement
Fix positive integers and . For placements of indistinguishable balls into indistinguishable boxes:
- the arbitrary placements are counted by the partitions of with at most parts, equivalently by the partitions of whose parts are all at most ;
- the injective placements are counted by when and by when ;
- the surjective placements are counted by .
Facts & Assumptions
Given: positive integers and .
Under the page conventions, an unlabelled-to-unlabelled placement is encoded by its nonzero occupancies written in nonincreasing order (Conventions for integer partitions, Ferrers diagrams, and the twelvefold-way table).
Partitions with at most parts are equinumerous with partitions whose parts are all at most (Partitions with at most k parts are equinumerous with partitions whose parts are all at most k).
Proof
By [L1], an arbitrary placement is determined by the list of its positive occupancies, written in nonincreasing order. These occupancies sum to , so they form a partition of ; because there are only boxes, there can be at most positive occupancies. Conversely, any partition of with at most parts becomes such a placement by reading its parts as the nonzero box occupancies. This proves clause 1 in its "at most parts" form.
A placement is surjective exactly when every box is occupied, so there are exactly positive occupancies. By step 1.1 these are exactly the partitions of into positive parts, which are counted by . This is clause 3.
A placement is injective exactly when every occupied box contains one ball. Therefore the positive occupancy list must be with entries. Such a list exists exactly when , and when it exists it is unique. This proves clause 2.
The second description in clause 1 follows from [L2].
Depends on
Used by
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Alexander Hulpke, Combinatorics notes (standard reference, not scraped)
- Darij Grinberg, Enumerative Combinatorics: class notes (standard reference, not scraped)