Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Unramified frobenius element exists uniquely

Statement

For finite Galois L/K and a nonzero prime Pp with e(P/p)=1, there is a unique FrobPD(P/p) satisfying FrobP(a)aNp(modP)(aOL). It is the arithmetic Frobenius element, the unique lift of the arithmetic Frobenius coset.

Facts & Assumptions

Given: The data and hypotheses of the statement.

[F1]

Arithmetic frobenius coset: For finite Galois L/K and nonzero Pp, the arithmetic Frobenius coset is the unique element of D(P/p)/I(P/p) corresponding under the residue isomorphism to xxNp on κ(P), where Np=κ(p). It is defined also when P is ramified. Its inverse is called geometric Frobenius. The quotient element is distinguished; a representative in D need not be unique.

[F2]

Orders of decomposition and inertia groups: For finite Galois L/K and nonzero Pp, writing e and f for its ramification index and residue degree, D(P/p)=ef,I(P/p)=e,D(P/p)/I(P/p)=f. The prime P is unramified over p if and only if its inertia group is trivial.

Proof

1.1

The assumption e=1 implies I is trivial. Consequently the quotient map DD/I is an isomorphism of groups, including when D itself is trivial.

F2
2.1

The coset defined by the arithmetic residue power map therefore has exactly one inverse image. Reduction of that image is the power map, which is precisely the displayed congruence on every residue representative, including zero. Conversely any element of D with those congruences has the same quotient image and hence equals it.

F1step 1.1

Depends on

Used by

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Sources