Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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Variance of a finite sum as the sum of all variances and covariances

Statement

For a finite family (Xi)i∈I, Var⁡ ⁣(∑i∈IXi)=∑i∈IVar⁡(Xi)+2∑{i,j}⊆ICov⁡(Xi,Xj). Equivalently, it is ∑i,j∈ICov⁡(Xi,Xj). The empty sum has variance zero, and the singleton formula is the identity. In the first display, the second sum is over two-element subsets of I.

Facts & Assumptions

Given: A finite family of random variables (Xi)i∈I.

[L2]

Covariance is symmetric and bilinear in finite linear combinations (Covariance is symmetric and bilinear in finite linear combinations).

Proof

technique · direct
1.1

By [L1] and bilinearity, Var⁡(∑iXi)=Cov⁡(∑iXi,∑jXj)=∑i,jCov⁡(Xi,Xj).

L1L2
2.1

Separate the diagonal terms, which are Var⁡(Xi), from the off-diagonal ordered pairs. Symmetry pairs the latter into twice the sum over unordered pairs.

step 1.1L1L2algebra
3.1

For an empty family every sum in step 1.1 is zero, and for a singleton only its diagonal term remains.

step 1.1step 2.1∎

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources