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CounterexampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Normalized polarization is undefined at darkness

Physical scope

A zero-amplitude classical ensemble in the two-component coherency-matrix model. It demonstrates a boundary of a normalization definition; it is not a reported dark-detector observation, a noise model, or an empirical claim.

Statement refuted

For every square-integrable two-component classical ensemble, the quotient P=S12+S22+S32/S0 defines a real degree of polarization.

Facts & Assumptions

Given: The one-point probability space Ξ={σ0} with P({σ0})=1, and the square-integrable two-component complex amplitude Z(σ0)=0.

[F1]

Classical two-component coherency matrix: Γ=E[ZZ†], S0=Γ11+Γ22, and the normalized degree is defined only when S0>0.

[A1]

Z(σ0)=0 on the declared one-point probability space.

Counterexample

1.1givenF1A1algebra

From [A1], ZZ†=0 at the sole sample point, so [F1] gives Γ=0 and S0=S1=S2=S3=0.

2.1step 1.1F1algebra∎

The proposed quotient therefore has denominator S0=0 and is undefined; the universal statement is false, even though the unnormalized cone inequality holds as 0≥0.

Remarks

This is a domain-of-definition counterexample. It makes no claim about a real detector's dark counts, background, resolution, or uncertainty.

Depends on

Dependency tree · 2 levels

Sources