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CounterexampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
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Unsteady pathlines differ from streamlines

Physical scope

Smooth kinematic velocity field on Newtonian spacetime, with pathlines and streamlines defined on the same spatial region. No momentum equation, constitutive law, or empirical flow is asserted.

Statement refuted

Whenever both curves exist on a common interval, for every C1 velocity field u:I×Ω→R3, every initial point x0∈Ω, and every frozen time t0∈I, the pathline X satisfying X(t0)=x0 equals the streamline through x0 at time t0 when the streamline parameter is identified with t−t0.

Facts & Assumptions

Given: An open time interval I, a spatial region Ω, and the definitions of pathline and frozen-time streamline from the stated velocity field.

[F1]

Classical frames, primitive quantities and SI units: a pathline solves dX/dt=u(t,X(t)); a streamline at fixed t0 solves dY/ds=u(t0,Y(s)) with s measured in seconds.

Counterexample

Given: Let I=R, Ω=R3, and u(t,x,y,z)=(αyt,β,0), where α≠0 has units s−2 and β≠0 has units m s−1. Choose frozen time t0=0 and initial point (x0,0,z0).

1.1givenF1algebra

Solve the pathline equations y˙=β, z˙=0, and x˙=αty(t) with y(0)=0, z(0)=z0, x(0)=x0. They give y(t)=βt, z(t)=z0, and x(t)=x0+αβt3/3.

2.1F1givenstep 1.1algebra

At frozen time t0=0, the velocity is u(0,x,y,z)=(0,β,0), so by [F1] the streamline through the same initial point is Y(s)=(x0,βs,z0). Under s=t−t0=t, its x-coordinate is constant, whereas step 1.1 has x(t)=x0+αβt3/3, which differs for every t≠0. Thus the pathline and streamline are distinct.

3.1givenstep 2.1algebra∎

Since ∂tu=(αy,0,0) is not identically zero, this is an unsteady field. The explicit distinct curves in step 2.1 refute the universal assertion for an unsteady flow.

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