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CounterexampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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A noncompact phase domain with no attained mixture maximum

Physical scope

A constructed continuous entropy extension that is positive and concave on a convex ambient domain but restricted to a noncompact generator set omitting its maximizing barycenter; it makes no material claim.

Statement refuted

Let d≥1, let K⊆C⊆Rd with K noncompact and C convex, and let P be a nonempty family of Borel probability measures on K sharing a prescribed barycenter. The statement refuted is that sup⁡P∈P∫Ks dP is always attained whenever s=s~∣K for a bounded, positive, continuous concave function s~:C→R. Here convexity of C means (1−t)x+ty∈C for x,y∈C and t∈[0,1], and concavity means

s~((1−t)x+ty)≥(1−t)s~(x)+ts~(y)(x,y∈C, t∈[0,1]).

Example

Let K=(−1,0)∪(0,1), which is noncompact: the open cover Un=(−1,−1/n)∪(1/n,1) for n≥2 has no finite subcover. Let C=[−1,1] and use dimensionless coordinate x. For constants s0>a>0 in J mol−1K−1, define the ambient entropy extension and its restriction by

s~(x)=s0−ax2(x∈C),s=s~∣K.

For x,y∈C and t∈[0,1],

s~((1−t)x+ty)=(1−t)s~(x)+ts~(y)+at(1−t)(x−y)2≥(1−t)s~(x)+ts~(y),

so s~ is concave on the convex ambient domain. It is continuous, bounded, and positive since s0−a>0. The admissible generator set K excludes the maximizing point x=0. Declare all Borel probability measures on K with fixed barycenter xˉ=0 feasible, with entropy per mole ∫Ks dP. For y∈K, define the point mass δy(A)=1 if y∈A and 0 otherwise for every Borel set A⊆K. It is countably additive because at most one set in a disjoint family can contain y, and δy(K)=1.

Facts & Assumptions

Given: The noncompact Borel domain K, the restricted entropy s, and all Borel probability measures on K with mean zero as the feasible family.

[F1]

The Borel sigma-algebra of a topological space, Probability measures and probability spaces, and Measure space and integral: Feasible mixtures are countably additive Borel probability measures of total mass one, and their integrals use the stated measure convention.

Counterexample

1.1givenF1algebra

Since 0<s0−a≤s(x)<s0 on K, every feasible s is nonnegative and bounded. For n≥2, put An:={x∈K:∣x∣≥1/n}. Their union is K; since P(K)=1, countable additivity implies P(An)>0 for some n. On An, s≤s0−a/n2, and on its complement s≤s0. For any nonnegative simple function φ≤s, the measure integral definition [F1] therefore gives

∫Kφ dP≤(s0−a/n2)P(An)+s0P(K∖An)=s0−aP(An)/n2<s0.

Indeed, refine the finitely many level sets of φ by An and its complement; each simple-function coefficient is bounded by the corresponding pointwise bound on that piece, so the simple-integral formula [F1] gives the inequality. The strict upper bound is independent of φ, hence its supremum also satisfies ∫Ks dP<s0.

2.1givenF1step 1.1algebra∎

For each 0<ϵ<1, the measure Pϵ=12δ−ϵ+12δϵ is a Borel probability measure on K, has mean zero, and satisfies ∫Ks dPϵ=s0−aϵ2. Letting ϵ↓0 shows that the supremum is s0. Step 1.1 shows that no feasible measure attains it. Thus the false statement fails even with a bounded positive continuous concave extension, because the admissible generator set excludes its maximizing barycenter.

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