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A continuous function on a closed rectangle has repeated Riemann integrals in every coordinate order, all equal to its multiple integral

Statement

Let Q=∏j<n[aj,bj]⊆Rn, where n≥1 and every aj<bj. If f:Q→R is continuous, then for every permutation of the coordinates the corresponding repeated Riemann integral exists and equals ∫Qf.

Facts & Assumptions

Given: A continuous real function f on a nondegenerate closed rectangle Q⊆Rn.

[L1]

Riemann--Fubini identifies the multiple integral with either iterated integral whenever the ordinary sections exist away from a content-zero exceptional set (Riemann--Fubini on product rectangles, with lower and upper section integrals and content-zero exceptional sections).

[L2]

Every continuous real function on a closed nondegenerate rectangle in positive dimension is Riemann integrable (Every continuous function on a closed nondegenerate rectangle in Rm is Riemann integrable).

[L3]

A continuous map from a compact metric space to a metric space is uniformly continuous (Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous).

Proof

technique · direct
1.1L2L3given

Every coordinate section is continuous, hence integrable by [L2]. Moreover f is uniformly continuous on the compact rectangle by [L3]; therefore integrating in one coordinate produces a continuous function of the remaining coordinates, since the difference of two section integrals is bounded by the interval length times the uniform oscillation of f.

2.1L1step 1.1

Apply [L1] to the first coordinate in a prescribed order. Step 1.1 makes the resulting function continuous, so the same argument applies to the next coordinate. Induction through the finite coordinate list gives the repeated integral.

3.1step 2.1algebra∎

For n=1 the repeated integral is the original integral. At every later stage [L1] preserves its value, so every coordinate order gives ∫Qf.

Depends on

Dependency tree · 2 levels

Sources