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Good grading and isotropic data for affine W-algebra reduction

Definition

Let g=⨁j∈12Zgj be a grading of a finite-dimensional complex simple Lie algebra induced by a semisimple grading element, so [gi,gj]⊆gi+j and the invariant form pairs gi with g−i. Let f∈g−1 be nilpotent. The grading is good for f if ad⁡f:gj→gj−1 is injective for j≥12 and surjective for j≤12. Use the invariant form normalized by def-cft-root-data-for-principal-w-levels and define ωf(u,v)=(f∣[u,v]),u,v∈g1/2. Choose a maximal isotropic subspace ℓ⊆g1/2 and put m=ℓ⊕⨁j≥1gj and χ=(f∣⋅)∣m. This is conditional data; this item does not assert that every nilpotent element has a good grading.

Facts & Assumptions

Given: The graded simple Lie algebra, the nilpotent f∈g−1, the normalized invariant form, and a grading satisfying the stated good-map conditions.

[F1]

Finite-dimensional simple complex Lie algebra: g is a finite-dimensional complex simple Lie algebra.

[F2]

Nilpotent element in a finite-dimensional Lie algebra: nilpotence is the adjoint condition.

[F3]

Root normalization and dual data for principal W levels and Dual Coxeter number for the normalized invariant form: the form is normalized using long roots of square length 2 and is invariant and nondegenerate. Only this form interface is used here; the dual-root realization issue does not enter the good-grading calculation.

Proof

1.1F1F2F3givenalgebra

The nilpotence convention for the supplied f is [F2]. The form ωf is skew because [u,v]=−[v,u]. Invariance gives ωf(u,v)=([f,u]∣v). The good-grading conditions make ad⁡f:g1/2→g−1/2 both injective and surjective, hence an isomorphism. Invariance of the form under the grading pairs g−1/2 nondegenerately with g1/2, so ωf is nondegenerate.

1.2givenF3algebra

All degrees occurring in m are positive. Thus the grading rule makes m a subalgebra and the invariant form vanish on m×m, since it pairs only opposite degrees.

2.1step 1.1algebra

A finite-dimensional nondegenerate skew form has a maximal isotropic subspace: if the space is nonzero, choose u≠0 and then v with ωf(u,v)=1; their span is nondegenerate, its orthogonal complement is nondegenerate of dimension two smaller, and induction supplies a Lagrangian there. Adding Cu gives an isotropic subspace of half the original dimension. The zero-dimensional case uses ℓ=0.

3.1step 1.1step 1.2algebra∎

The character χ vanishes on every graded component except degree 1. In [m,m], only [ℓ,ℓ]⊆g1 can contribute to that component, and χ([u,v])=ωf(u,v)=0 for u,v∈ℓ. Hence χ([m,m])=0, so χ is a Lie algebra character.

Proof status

The definition and its consequences for supplied good-grading data are local. The general existence of such data for every nilpotent f is not asserted here; this item also depends on the escalated general root-data interface in [F3].

Depends on

Dependency tree · 2 levels

Sources