Alphabeta Math
DefinitionDefinition: AI-adaptedProof: Not applicable
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A norm on a real vector space, the induced metric, and the dictionary with the metric axioms

Definition

Throughout this page R is the complete ordered field (Complete ordered field (least-upper-bound property)) constructed in this library, in particular a field, so that "vector space" below always means vector space over R (Vector space over a field).

Let V be a vector space over R, with zero vector 0V. A norm on V is a function N:V→R such that for all u,v∈V and all λ∈R:

  • (N1) Separation. N(v)=0 if and only if v=0V.
  • (N2) Absolute homogeneity. N(λv)=∣λ∣ N(v), the absolute value being that of Absolute value in an ordered field.
  • (N3) Triangle inequality. N(u+v)≤N(u)+N(v).

A normed space is a pair (V,N) consisting of a vector space V over R and a norm N on it. When only one norm is in play we write ∥v∥ for N(v); when several are, the norm is always named.

The values of a norm are real numbers. The codomain is R, so N(v) is an honest element of the complete ordered field and no infinite value is permitted. The same real-valued codomain is required of a metric by Metric space: d(x,y)=0 iff x=y, symmetry, and the triangle inequality; pseudometric and ultrametric.

Nonnegativity is a theorem, not an axiom

Many texts add a fourth condition N(v)≥0. It is redundant. Applying (N2) with λ=−1 gives N(−v)=∣−1∣ N(v)=N(v) (Basic properties of the absolute value, In any vector space 0Fv=0V, λ0V=0V, (−λ)v=−(λv), (−1F)v=−v, and λv=0V forces λ=0F or v=0V for (−1)v=−v), and then (N3) with u=v and −v gives

0  =  N(0V)  =  N(v+(−v))  ≤  N(v)+N(−v)  =  N(v)+N(v),

where N(0V)=0 is (N1). So N(v)+N(v)≥0, and if N(v)<0 then N(v)+N(v)<0 by addition of inequalities, which trichotomy forbids (Complete ordered field (least-upper-bound property)). Hence N(v)≥0 for every v∈V.

Consequently the verification of a candidate norm has three things to check and not four, exactly as the verification of a candidate metric has three and not four (Metric space: d(x,y)=0 iff x=y, symmetry, and the triangle inequality; pseudometric and ultrametric, Nonnegativity of a metric is a consequence of the other axioms, not an axiom). No item in this library assumes nonnegativity of a norm before the argument above.

The induced metric

Let N be a norm on V and define

dN(u,v)  :=  N(u−v)(u,v∈V),

where u−v=u+(−v) (Vector space over a field). Then dN is a metric on V (Metric space: d(x,y)=0 iff x=y, symmetry, and the triangle inequality; pseudometric and ultrametric), and the three axioms are the three conditions above, in order:

A normed space is therefore a metric space, and every notion defined for metric spaces — open set (The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement), convergence, Cauchyness, continuity, compactness — is available in it with no further definition. This library never introduces a second notion of any of them for normed spaces.

Two properties an arbitrary metric need not have

The metric dN satisfies, for all u,v,w∈V and λ∈R:

  • translation invariance, dN(u+w,v+w)=N((u+w)−(v+w))=N(u−v)=dN(u,v);
  • absolute homogeneity, dN(λu,λv)=N(λ(u−v))=∣λ∣ dN(u,v), by (N2).

Not every metric on a vector space arises from a norm, and homogeneity is what fails. The published bounded remetrisation min⁡(d,1) and d/(1+d) are metrics uniformly equivalent to d, so every metric space carries a bounded metric with the same topology replaces a metric d by d′=min⁡{d,1}, a metric with the same topology whose values never exceed 1; on a vector space V containing a vector v with d(v,0V)>0 this d′ cannot be dM for any norm M, since absolute homogeneity would force d′(λv,0V)=∣λ∣ d′(v,0V), which is unbounded in λ, while d′ is bounded by 1. So the passage from norms to metrics is not reversible, and a statement about a metric on a vector space is strictly weaker than the corresponding statement about a norm.

Remarks

Depends on

Dependency tree · 2 levels

Sources