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One-loop electron-muon QED threshold matching and running

Physical scope

The source-reported one-loop decoupling-subtraction running of the electromagnetic coupling in QED with an electron and a muon; no experimental value, all-orders result, or model-independent threshold claim.

Example

Use natural units c=ℏ=1 and Minkowski signature η=diag⁡(−,+,+,+). In four spacetime dimensions assign mass dimensions [xμ]=−1, [∂μ]=1, [Aμ]=1, [Fμν]=2, [ψf]=3/2, [eDS]=[αDS]=0, and [me]=[Mμ]=[μ]=[Q]=1. For x∈R1,3, regard Aμ(x), ψe(x), and ψμ(x) as formal perturbative fields, with no classical-solution regularity or nonperturbative operator domain assumed. The potential A=Aμdxμ is a real U(1) one-form and F=dA has components Fμν=∂μAν−∂νAμ. The fields ψe,ψμ are four-component complex Dirac spinors; use Clifford matrices satisfying {γμ,γν}=−2ημν and the Dirac adjoint ψˉ=ψ†γ0. At each fixed renormalization scale μ in an active interval, let eDS(μ)>0 and use Dν=∂ν+ieDS(μ)Aν for fields of charge −eDS(μ), with gauge kinetic term −14FμνFμν. For a real dimensionless gauge parameter χ(x), the convention is A↦A+dχ and ψf↦e−ieDS(μ)χψf. Define the dimensionless running coupling by αDS(μ)=eDS(μ)2/(4π). The decoupling-subtraction (DS) convention uses minimal subtraction within each interval of active charged fields, removes a charged field from the low-energy theory below its threshold, and matches the coupling continuously at that threshold. Set αDS(me)=αphys>0 as the low-energy boundary condition. The source-reported one-loop DS flow has two active Dirac fields for μ>Mμ, one for me<μ<Mμ, and none for μ<me. For q>0, define Re(q)=1αphys−13πlog⁡ ⁣(q2me2) and Rμ(q)=1αphys−13πlog⁡ ⁣(Mμ2me2)−23πlog⁡ ⁣(q2Mμ2). For positive evaluation scale Q of mass dimension one, require Re(q)>0 for every q∈[me,Q] when me<Q<Mμ; for Q>Mμ, require Re(q)>0 for every q∈[me,Mμ] and Rμ(q)>0 for every q∈[Mμ,Q]. The corresponding one-loop solutions are: 1αDS(Q)=1αphys−13πlog⁡ ⁣(Q2me2)(me<Q<Mμ), and 1αDS(Q)=1αphys−13πlog⁡ ⁣(Mμ2me2)−23πlog⁡ ⁣(Q2Mμ2)(Q>Mμ). The two expressions agree continuously at Q=Mμ. These are solutions of the supplied one-loop renormalization-group equations; they are not measured values, exact all-orders predictions, or numerical error estimates.

Facts & Assumptions

Given: The QED field content and conventions in the Example, positive masses me<Mμ, a positive low-energy coupling αphys, the source-reported piecewise one-loop DS beta equations and boundary conditions, and an evaluation scale Q for which the displayed solution remains positive.

[F1]

Finite renormalization schemes and Wilson coefficient vectors: the renormalization scale is distinct from the cutoff, and its logarithm relative to a reference scale in J is dimensionless.

[F2]

Finite-order EFT threshold matching map: the matching map takes high-energy coefficient data to lower-energy coefficient data and identifies the selected renormalized amplitudes through the declared truncation with the same infrared regulator.

[F3]

Burgess, full EFT review, §4.1.4, equation (85) and its following boundary conditions: the source reports μ2 dαDS/dμ2=2αDS2/(3π) above Mμ, αDS2/(3π) between me and Mμ, and zero below me, with continuity at Mμ and αDS(me)=αphys. This is a one-loop perturbative input, not an empirical observation. The first branch of printed equation (86) has an apparent typographical error: its denominator Mμ2 conflicts with the equation (85) flow and the stated low-energy boundary condition. The Verification derives the branch directly from (85) and that boundary condition.

[A1]

The QED field content and DS threshold convention in the Example are the selected model assumptions. No measured value of either mass or coupling is supplied.

[A2]

The one-loop beta equations are used as a truncated source-reported calculation. Higher loops and higher-dimension operators are omitted, with no numerical bound asserted.

Verification

1.1givenF1F3A2algebra

On an interval with fixed active-field count n∈{1,2}, put u=log⁡(μ2/μ∗2) for any fixed reference scale μ∗ in that interval. By [F3], dαDS/du=nαDS2/(3π). Since αDS>0, differentiation of its reciprocal gives d(1/αDS)/du=−n/(3π). Integrating between two scales in this interval yields the corresponding affine function of log⁡μ2.

2.1F3A1step 1.1algebra

Between me and Mμ, take n=1 and use the boundary value αDS(me)=αphys. Step 1.1 gives 1/αDS(Q)=1/αphys−(1/(3π))log⁡(Q2/me2) for me<Q<Mμ.

3.1F2F3step 1.1step 2.1algebra

At μ=Mμ, the low-energy value is 1/αDS(Mμ)=1/αphys−(1/(3π))log⁡(Mμ2/me2). The DS boundary condition sets the high-energy coupling equal to this value at the threshold. Above it n=2, so integrating step 1.1 from Mμ to Q gives 1/αDS(Q)=1/αphys−(1/(3π))log⁡(Mμ2/me2)−(2/(3π))log⁡(Q2/Mμ2) for Q>Mμ.

4.1F3step 2.1step 3.1algebra∎

Setting Q=Mμ in the upper expression removes its last logarithm and gives exactly the lower expression at the threshold. Setting Q=me in the lower expression recovers αphys. Thus the piecewise one-loop solution satisfies both stated boundary conditions and is continuous at the threshold.

Depends on

Dependency tree · 2 levels

Sources