Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An all-zero Monte Carlo sample can report zero standard error

Example

Let n≥2 and p∈(0,1). On the product probability space {0,1}n with independent Bernoulli(p) coordinates X1,…,Xn, define Xˉn:=n−1∑j=1nXj, sn2:=(n−1)−1∑j=1n(Xj−Xˉn)2, and se^n:=sn/n. The event that all coordinates are zero has probability (1−p)n>0. On that event Xˉn=sn2=se^n=0, although the target mean is p>0 and the population variance is p(1−p)>0, so the absolute error is p. This is an exact finite-sample probability-model example, not an experimental observation; it shows that a zero plug-in standard error in one realization does not establish zero population variance or zero estimation error.

Facts & Assumptions

Given: n≥2, p∈(0,1), and X1,…,Xn the coordinate random variables on the stated Bernoulli product probability space.

[F1]

Identical distribution and IID families: IID means common law and mutual independence.

[F2]

IID Monte Carlo sample mean, variance, and standard error: Xˉn=n−1∑j=1nXj, sn2=(n−1)−1∑j=1n(Xj−Xˉn)2, and se^n=sn/n for n≥2.

[F3]

Moments, variance, and covariance on a probability space: for square-integrable X, Var⁡(X)=E[(X−E[X])2].

Verification

1.1F1givenalgebra

Mutual independence gives P(X1=⋯=Xn=0)=∏j=1nP(Xj=0)=(1−p)n>0.

2.1F2givenstep 1.1

On this event all Xj and Xˉn are zero, so [F2] gives sn2=0 and se^n=0.

3.1F3givenstep 1.1algebra∎

For a Bernoulli(p) variable Xj, Xj2=Xj pointwise, hence E[Xj]=p and [F3] gives Var⁡(Xj)=E[Xj2]−p2=p(1−p)>0. On the event in step 1.1 the sample mean differs from this target by p.

Depends on

Dependency tree · 2 levels

Sources