Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
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Barotropic Kelvin and Bernoulli with exact hypotheses — worked interpretation

Physical scope

Constructed exact barotropic Euler field with specified parameters; not an empirical claim about viscous fluids.

Example

Choose P(ρ)=4 m2 s−2ρ, Ω=1 s−1, ρc=ρref=1 kg m−3, and an open cylinder with radius R=2 m, half-height H=1 m. The exact steady density is ρ(r)=er2/(8 m2) kg m−3 and u=Ω(−y,x,0), with x,y in metres. On a material circle of radius 1 m, Γ=2π m2 s−1. Between r=0 and r=1 m, Bernoulli value changes by 1 m2 s−2; each circular streamline still has constant value.

Facts & Assumptions

Given: P=c2ρ with c=2 m s−1, Ω=1 s−1, ρc=ρref=1 kg m−3, and the exact solid-rotation field.

[F1]

Barotropic Kelvin and Bernoulli with exact hypotheses — conditional physical prediction: circulation is 2πΩs2 and Bernoulli is a constant plus Ω2r2 in this smooth barotropic Euler model.

[F2]

Formal parameterized fluid systems and observables: for a closed piecewise-C1 oriented curve, circulation is ∮γu⋅dr=∫u(γ(s))⋅γ′(s) ds. Here the material circle in the z=0 plane is X(t,θ)=((1 m)cos⁡(θ+Ωt),(1 m)sin⁡(θ+Ωt),0) for t∈R seconds and 0≤θ≤2π, with Ω=1 s−1; ∂tX=u(t,X) and Γ(t)=∫02πu(t,X(t,θ))⋅∂θX(t,θ) dθ.

Proof

1.1givenF1F2algebra

For the radius-one material circle X in [F2], its circulation is Γ(t)=∫02πu(t,X(t,θ))⋅∂θX(t,θ) dθ=2πΩ(1 m)2=2π m2 s−1.

2.1givenF1step 1.1algebra∎

The Bernoulli difference from r=0 to r=1 m is 12(12−02)=1 m2 s−2. It is a between-streamline difference; each circle keeps fixed r.

Depends on

Dependency tree · 2 levels

Sources