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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-11-04 (gpt-6.1-sol)
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Flat complex torus: canonical triviality and non-full SU(n) holonomy for n ≥ 2

Example

Assume full AC. Let n≥1, let Λ=∑a=12nZλa⊂Cn be a full lattice generated by a real basis of Cn≅R2n, and put X=Cn/Λ. The standard Euclidean Hermitian metric g0=∑j(dxj2+dyj2) descends, with real fundamental form ω0=∑jdxj∧dyj. Then X is a compact connected Kähler manifold and its canonical bundle is trivialized by the descended nowhere-zero holomorphic form Ω0=dz1∧⋯∧dzn. Let D be the Levi-Civita connection of the descended metric and define its curvature by RD(X,Y)Z:=DXDYZ−DYDXZ−D[X,Y]Z. The metric is flat when RD=0; in this example it is flat and has trivial holonomy. For n≥2, trivial holonomy is a proper subgroup of SU(n), so the broad Calabi–Yau convention does not force exact SU(n) holonomy. For n=1, SU(1) is itself trivial and this example does not separate the groups.

Facts & Assumptions

Given: Full AC; a real basis λ1,…,λ2n of Cn; the standard complex structure and Euclidean metric; and the broad convention from the preceding item.

[A1]

Full AC is the choice-function principle of The Axiom of Choice and is inherited from the complete convention supplier.

[F1]

The broad convention requires a connected compact Kähler n-fold with a specified holomorphic trivialization of its canonical line bundle; it adds no holonomy equality assumption (Compact Calabi–Yau manifold conventions).

[F2]

For a supplied smooth Riemannian metric the Levi-Civita connection is the unique torsion-free, metric-compatible connection; parallel transport is defined by parallel sections, and holonomy is generated by transports around based loops (Compact Calabi–Yau manifold conventions).

Verification

technique · direct
1.1A1givenconstructalgebra

The real-linear isomorphism L:R2n→Cn sending the standard basis to (λa) maps Z2n onto Λ, so Λ is discrete; bounded sets meet Λ finitely because their inverse images under L are bounded and bounded sets meet Z2n finitely. For every compact K⊂Cn, if (K+λ)∩K≠∅ then λ∈K−K, a bounded set meeting the lattice finitely; this proves proper discontinuity, and freeness follows because a translation fixing a point has vector 0. The shortest nonzero lattice length is positive. Distinct orbits have positive distance: for fixed representatives z,w, only finitely many λ can satisfy ∣z−(w+λ)∣≤R for any fixed R, so if no w+λ=z the minimum distance is positive. Small disjoint balls therefore separate distinct orbits and give Hausdorff quotient charts; choosing their radii below half the shortest lattice length makes their nonidentity translates disjoint. The chart transitions are translations and therefore holomorphic. The closed fundamental parallelepiped {∑ataλa:0≤ta≤1} is compact and surjects onto X, proving compactness; the quotient map is continuous and surjective, proving connectedness.

2.1F1givenstep 1.1algebra

Translations preserve g0, J, and ω0, so these descend. The descended ω0 is real, positive, and closed, hence Kähler. Translations also preserve Ω0; it descends to a nowhere-zero holomorphic section of KX, which trivializes KX by the preceding convention [F1].

2.2F2givenstep 1.1algebra

On Cn, define DX(∑afaEa)=∑aX(fa)Ea for the constant real coordinate frame (Ea)=(∂x1,∂y1,…,∂xn,∂yn). Deck translations have identity differential, so this connection descends and the frame remains global and parallel. The fields Ea commute, giving TD(Ea,Eb)=0; torsion is tensorial, so TD=0. Since g0(Ea,Eb)=δab is constant and DEa=0, the connection is metric-compatible, hence D is Levi-Civita by [F2]. Its curvature annihilates each parallel Ea, and since these form a frame, RD=0. Along any piecewise smooth loop, a parallel field has constant coefficients in this global frame, so its endpoint equals its initial value; the holonomy group is trivial.

3.1step 2.2algebra∎

For n≥2, choose t∉2πZ. The matrix diag⁡(eit,e−it,1,…,1) is unitary, has determinant 1, and is not the identity; hence SU(n) is nontrivial and cannot equal the trivial holonomy group. For n=1, SU(1)={1}, as stated.

Depends on

Dependency tree · 2 levels