Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Explicit physical electric/occupation basis state

Example

Take two vertices v1,v2, one oriented link e:v1→v2, one fermion mode at each vertex, and background bv1=1,bv2=0. Let ψ be the tensor of the zero-electric Fourier vector and the occupation vector with the v1 mode occupied and the v2 mode empty. This is a concrete nonzero state in the fixed-background physical sector.

Facts & Assumptions

Given: The conditional finite-graph CAR model, one oriented link, and the chosen backgrounds.

[F1]

Gauss operators, gauge group and nonempty physical projection: for the conditional compact-rotor/CAR data, a normalized Fourier/occupation basis vector lies in Hphys=⋂xker⁡Gx exactly when every integer Gauss label γx is zero, where γx is outgoing link label minus incoming link label minus site occupation plus bx.

Verification

Given: [F1] and the stated graph, occupation, and link labels.

1.1F1given

The vector ψ is a normalized Fourier/occupation basis vector: its link label is ne=0, its site occupations are nv1=1,nv2=0, and these occupations lie in the finite fermion Fock basis.

2.1F1step 1.1algebra∎

At v1, γv1=ne−(nv1−bv1)=0−(1−1)=0. At v2, γv2=−ne−(nv2−bv2)=0−(0−0)=0. Thus every Gauss operator annihilates ψ, so ψ∈Hphys and the physical projection is nonzero.

Depends on

Dependency tree · 2 levels

Sources