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A finite supersymmetric pair with Witten index one

Physical scope

A finite-dimensional supersymmetric quantum-mechanical Hilbert-space example with exact discrete trace. It is not a continuum QFT, an observed system, or a claim about a naturally realized particle.

Example

Assume ACω and use natural units c=ℏ=1. The model has time t∈R, with time units, and spatial domain the positively oriented singleton X={∗} with its unique zero-dimensional metric. Its spacetime is M=R×X, with flat metric dt2 and orientation dt; neither domain has a boundary. Let E∗>0 be an energy and let H=C3 have orthonormal basis e0,e+,e−. The state bundle is the trivial bundle M×C3→M; the internal/gauge group is {1}, acting as the identity on each fibre. There are no spatial field bundles or additional matter representations. State histories are C1 curves ψ:R→H, and the adopted dynamical postulate is i dψ/dt=Kψ, with K specified below. The Hilbert space and all matrices are supplied directly, with no continuum regulator, functional measure, or path-integral claim. Give H the grading H+=span⁡{e0,e+} and H−=span⁡{e−}, with Γ=+I on H+ and −I on H−. On the full domain D(Q)=H, define the self-adjoint odd supercharge by Qe0=0, Qe+=E∗e−, and Qe−=E∗e+. Set K=Q2. The Witten index is 1 for every β>0.

Example references

Facts & Assumptions

Given: The finite-dimensional graded Hilbert-space model and the operators in the Example; β>0 has inverse-energy units.

[A1]

Assume ACω, as used by the exact Hilbert and trace definitions. The Axiom of Countable Choice (ACω)

[F1]

Physical Witten index and selected BPS sector: for a pure-point graded physical index datum with trace-class heat operators, the Witten index is the absolutely convergent even-minus-odd diagonal sum in a supplied compatible basis.

Verification

Given: [A1], [F1], and the finite-dimensional model stated in the Example.

1.1A1givenalgebra

The matrix of Q in (e0,e+,e−) is (00000E∗0E∗0), which is self-adjoint. It sends each parity subspace into the other and annihilates e0, so ΓQ=−QΓ. Squaring gives Ke0=0 and Ke+=E∗e+, Ke−=E∗e−.

2.1A1F1step 1.1algebra

Thus the heat operator is diagonal with eigenvalues 1,e−βE∗,e−βE∗ on (e0,e+,e−); it is finite rank and trace class, and this basis is a complete compatible basis for the pure-point datum under the trace conventions using [A1].

3.1F1step 2.1algebra∎

By [F1], WE(β)=⟨e0,e0⟩+e−βE∗⟨e+,e+⟩−e−βE∗⟨e−,e−⟩=1+e−βE∗−e−βE∗=1. The single even zero mode supplies the net index; the positive-energy even/odd pair cancels for every β>0.

Depends on

Dependency tree · 2 levels

Sources