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A Finite BV Density Counted Once

Example

In BV Density Bridge and Pushforward Master Defect, fix a finite Darboux chart, even classical master action S0, even field-only f, and even parameter σ. Let μσ=eσf and ρσ=μσ2ρ0. Then the representations I1 with Δρσ and J1=I1−σf with Δ0 have the same one-loop defect. Pairing J1 with Δρσ instead adds the spurious term −σ(S0,f). Here σ is a finite variation parameter, not a continuum Weyl anomaly, and no prior calculation is alleged to have double-counted a density.

Facts & Assumptions

Given: A fixed finite Darboux chart, even field-only f, and the finite density/action bridge of [F1].

[F1]

BV Density Bridge and Pushforward Master Defect: Δρ=Δ0+(log⁡μ,−), J1=I1−log⁡μ, and (S0,I1)−ΔρS0=(S0,J1)−Δ0S0.

Proof

1.1F1algebra

Since log⁡μσ=σf, Δρσ=Δ0+σ(f,−) and J1=I1−σf. The even shifted-skew rule gives (f,S0)=(S0,f), so (S0,I1)−ΔρσS0=(S0,I1)−Δ0S0−σ(f,S0)=(S0,I1−σf)−Δ0S0. This is equality of the two defect representatives.

2.1F1step 1.1algebra∎

If one instead retains J1 and also uses Δρσ, the defect becomes (S0,J1)−Δ0S0−σ(f,S0), differing from the reference-density defect by −σ(S0,f). The term is exactly the same density variation already used in defining J1, so the finite example identifies the algebraic double count without alleging that it occurred in a physical source calculation.

Depends on

Dependency tree · 2 levels

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