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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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A perfectly retained bit gives zero conditional entropy reset bound

Physical scope

A calculated finite correlated-memory model illustrating the theorem's retained-register condition; no measurement or reset apparatus is described.

Example

Take memory and register bits M,R∈{0,1} with joint law p(0,0)=p(1,1)=1/2 and all other probabilities zero. Retain R and reset M to 0.

Facts & Assumptions

Given: The finite joint law and the physical assumptions of Conditional work bound for finite memory reset.

[F1]

Conditional entropy of finite memory given side information: H(M,R)=H(R)+H(M∣R).

[F2]

Conditional work bound for finite memory reset: the reset work bound uses H(M∣R), not H(M).

Verification

Given: The specified perfectly correlated two-bit distribution.

1.1givenF1algebra

The memory marginal is uniform, so H(M)=log⁡2. Given either value of R, the conditional law of M is a point mass; hence each conditional entropy is zero and H(M∣R)=0.

2.1F2step 1.1algebra∎

Therefore the theorem yields only W≥0 for this reset under its stated thermodynamic assumptions, while the unconditioned memory entropy is log⁡2. It does not imply a kBTblog⁡2 lower bound for this correlated preparation.

Depends on

Dependency tree · 2 levels

Sources