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Finite bath can stabilize negative heat capacity exchange

Example

Take a negative-capacity subsystem at an interior energy E∗ with Gibbs-volume temperature T∗>0 and capacity CG(E∗)<0, as in Finite-bath entropy curvature and specified exchange stability. Set Cb=∣CG(E∗)∣/2. For any energy offset E0∈R in joules, reference temperature Tref>0 in kelvin, and additive entropy constant S0 in J K−1, take Sb(Eb)=Cblog⁡(Eb−E0CbTref)+S0,Eb>E0, and choose Eb=E0+CbT∗. The argument of the logarithm is dimensionless.

Facts & Assumptions

Given: A negative-capacity finite subsystem at common temperature T∗ and the selected finite-bath exchange model.

[F1]

For the specified finite-bath entropy and exchange law, 0<Cb<∣CG∣ gives strict negative combined-entropy curvature and local exponential attraction under x˙=LStot′(x). (Finite-bath entropy curvature and specified exchange stability)

Verification

1.1givenalgebra

Differentiating the displayed bath entropy gives Sb′(Eb)=Cb/(Eb−E0), so Tb=1/Sb′(Eb)=(Eb−E0)/Cb and dEb/dTb=Cb. The chosen Eb makes Tb=T∗.

2.1F1step 1.1algebra

Since Cb=∣CG∣/2, the reciprocal-capacity sum is 1/CG+1/Cb=−1/∣CG∣+2/∣CG∣=1/∣CG∣>0. At the matched-temperature critical point, [F1] gives Stot′′=−1T∗2(1CG+1Cb)=−1T∗2∣CG∣<0. Thus the combined entropy has a strict local maximum in this exchange direction.

3.1F1step 2.1∎

The selected effective law x˙=LStot′(x) has nonnegative entropy production and exponentially attracts this local maximum by [F1]. This is a constructed mathematical reservoir model, not empirical data or a generic gravitational stability conclusion.

Depends on

Dependency tree · 2 levels

Sources