Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Abelian-group model for spectral-sequence computations

Statement

Abelian groups and homomorphisms form an abelian category. Kernels and images are the ordinary subgroup kernels and images, and cokernels are coset quotients. In particular Z, Z/2, Z/4 and their finite products are legitimate objects for filtered-complex computations. Multiplication by 2 on Z is injective with cokernel Z/2.

Facts & Assumptions

Given: Abelian groups and additive homomorphisms, with the indicated integer and congruence constructions.

[F1]

An additive category with kernels and cokernels is abelian when its canonical coimage-to-image map is an isomorphism (Abelian category).

[F2]

Group homomorphisms preserve the group operation (Monoid homomorphism and group homomorphism).

[F3]

The integers form a totally ordered commutative ring (The integers form a totally ordered ring).

[F5]

An equivalence relation gives its set of equivalence classes (Equivalence relation, equivalence class, and the quotient set A/∼).

[F6]

Division by a positive integer has a unique remainder between zero and that integer (Division with remainder in Z: for a∈Z and b>0 there are unique q,r∈Z with a=qb+r and 0≤r<b).

Proof

technique · direct
1.1F2

For abelian groups A,B the homomorphisms form an abelian group under (f+g)(a)=f(a)+g(a): additivity follows from commutativity in B, with zero map and pointwise negatives as identity and inverses. The group laws hold pointwise. Composition is bilinear because each map is additive [F2]. Identities and composites are homomorphisms by the same calculation, so this is a preadditive category.

2.1step 1.1

The one-element group 0 is both initial and terminal. The product group A×B with coordinate operations has projections and injections a↦(a,0), b↦(0,b). A pair of maps T→A,B induces t↦(f(t),g(t)), uniquely by coordinates. Maps A→T and B→T induce (a,b)↦f(a)+g(b), uniquely since (a,b)=(a,0)+(0,b). These are its product and coproduct properties. Iterating yields every finite biproduct, including the empty one 0.

2.2F2step 1.1

For f:A→B, the subset K={a:f(a)=0} is a subgroup: f(0)=0 follows from f(0)=f(0)+f(0), and f(a−a′)=f(a)−f(a′). Any homomorphism killed by f has values in K and factors uniquely through its inclusion. The image I={f(a):a∈A} is likewise a subgroup, since f(a)-f(a')=f(a-a').

3.1F2F5step 2.2

For a subgroup I⊆B define b∼b' by b-b'∈I. Zero, negation and addition in I prove reflexivity, symmetry and transitivity. On the quotient set of [F5], define [b]+[c]=[b+c]; changing b,c by elements of I changes their sum by an element of I, so addition is well defined, and the group laws descend. A homomorphism h:B→T vanishes on I exactly when b↦h(b) is constant on each coset: one direction follows from h(b)-h(b')=h(b-b'), and the other by comparing i and 0 for i∈I. Thus [b]↦h(b) is the unique quotient homomorphism. With I=im f, this is a cokernel of f.

4.1F1step 1.1step 2.1step 2.2step 3.1

The kernel of B→B/I is exactly I since [b]=[0] iff b∈I. Consequently the categorical image of f is I, and its coimage is A/K. The canonical comparison [a]↦f(a) is well defined, is onto I by definition, and is injective since f(a)=f(a') iff a-a'∈K. Its inverse is the uniquely specified relation sending f(a) to [a], not a chosen representative function; it is additive because both maps preserve addition. Hence [F1] applies to steps 1.1–3.1 and proves the abelian-category assertion.

5.1F3F4F6step 2.1step 3.1∎

By [F3] the additive integers are an abelian group. If 2a=0 and a>0, positivity gives 2a>0; if a<0 it gives 2(-a)>0. Thus a=0, proving injectivity. Its image is 2ℤ and its cokernel is ℤ/2ℤ by step 3.1, with the congruence operations of [F4]. Division [F6] for divisors 2 and 4 gives exactly the distinct residue lists {0,1} and {0,1,2,3}. Their additions are modulo 2 and 4, so 1+1=0 in ℤ/2 and 1+1=2≠0, 2+2=0 in ℤ/4. Finite products have the coordinate operations of step 2.1.

Source notes

Stacks, §12.5, Definition 12.5.1 and Lemmas 12.5.11–15. The finite categorical argument below is supplied locally.

Depends on

Dependency tree · 2 levels

Sources