Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
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Sums, products, absolute values, finite maxima and minima, and quotients of continuous real-valued maps on a topological space are continuous where defined

Statement

Let f,g:X→R be continuous maps from a topological space. Then f+g, fg, ∣f∣, max⁡(f,g), and min⁡(f,g) are continuous. On the open cozero set coz⁡(g), the quotient f/g is continuous. The same holds for every finite sum, product, maximum, or minimum of continuous real-valued maps.

Facts & Assumptions

Proof

technique · direct
1.1L2

Addition is continuous at (a,b) because ∣s−a∣,∣t−b∣<ε/2 gives ∣(s+t)−(a+b)∣<ε. Multiplication is continuous there: after requiring ∣t−b∣<1, one has ∣st−ab∣≤∣s−a∣∣t∣+∣a∣∣t−b∣<∣s−a∣(∣b∣+1)+∣a∣∣t−b∣, which is less than ε when both coordinate errors are smaller than ε/(2(∣a∣+∣b∣+1)). These coordinate conditions describe product neighbourhoods, so both operations are continuous.

2.1step 1.1L1L2

The reverse triangle inequality ∣∣s∣−∣t∣∣≤∣s−t∣ makes absolute value continuous. Consequently max⁡{s,t}=s+t+∣s−t∣2,min⁡{s,t}=s+t−∣s−t∣2 are continuous by step 1.1 and composition.

2.2step 1.1L1F1L2

Reciprocal is continuous at b≠0: if ∣t−b∣<∣b∣/2, then ∣t∣>∣b∣/2 and ∣1t−1b∣=∣t−b∣∣t∣∣b∣<2∣t−b∣∣b∣2. Thus division (s,t)↦s/t is the product of s and 1/t and is continuous on R×(R∖{0}); moreover coz⁡(g) is open by [F1].

3.1L1step 1.1step 2.1

The map (f,g):X→R2 is continuous by [L1], so composing it with the operations of steps 1.1 and 2.1 gives continuity of f+g, fg, max⁡(f,g), and min⁡(f,g); composing f with absolute value gives continuity of ∣f∣.

3.2L1step 2.2

Restricting f and g to coz⁡(g) and composing their product map with division gives continuity of f/g there.

4.1step 3.1∎

Iterating the binary operations of step 3.1 proves the finite assertions.

Depends on

Dependency tree · 2 levels

Sources