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LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passverified 2026-11-05 (gpt-6.1-sol)
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Irreducible extremal cyclic Virasoro modules in boundary Fock spaces

Statement

Use the oscillator spaces, modes and screening coefficients of the rank-one oscillator data. Fix integers p≥2 and 0≤i≤p−2, and set d=p−1−i,β=i/(2p),δ=(2p−2−i)/(2p),c=1−6(p−1)2/p, an=((2pn+d)2−(p−1)2)/(4p),bn=((2pn−d)2−(p−1)2)/(4p). Then the actual cyclic Virasoro modules generated by the indicated Fock vacua satisfy U(Vir)e(β−n)α≅L(c,an),n≥0, U(Vir)e(δ−n)α≅L(c,bn),n≥1. Their L0-characters are respectively qan−qbn+1∏m≥1(1−qm),qbn−qan∏m≥1(1−qm). Here L(c,h) is the unique simple highest-weight quotient of the ordinary Verma module. These are full algebraic modules at all grades; no truncation is asserted.

Facts & Assumptions

Given: The parameters, oscillator spaces, modes and actual cyclic modules in the Statement.

[F1]

Rank-one Feigin–Fuchs oscillator spaces and long-screening coefficients gives the polynomial charge spaces. Their degree-N monomial basis has the partition dimension P(N).

[F2]

Background-charge oscillator modes and integral long screenings proves the actual Virasoro action, vacuum highest weights and integral-charge screening commutation for every integer p≥2 used here.

[F3]

Reflected oscillator pairing and transpose of the long screening proves the degreewise nondegenerate pairing at reflected charge t∗=(p−1)/p−t, with Lm∗=L−m and the exact screening transpose.

[F4]

Exact lengths of boundary long-screening strings proves the exact nonzero maximal powers Q2ne(β−n)α and Q2n−1e(δ−n)α and their next-power vanishing.

[F5]

Single-chain maximal submodules at boundary Virasoro central charges identifies the first embedded Verma as the maximal proper submodule. For M(c,an) its first grade is (i+1)(2n+1) and highest weight bn+1; for M(c,bn) they are 2nd and an.

[F6]

PBW basis and grades of Virasoro Verma modules gives the partition dimension and negative PBW word basis at every Verma grade.

Proof

Here a singular vector means a nonzero L0-eigenvector annihilated by every Lm with m>0. This is exactly the highest-weight-vector condition stated in [F2].

1.1F1F2F4givenalgebra

The oscillator monomials ∏mxmkmetα, where km∈Z≥0 is finitely supported, have degree N=∑mkm and are indexed by partitions of N, so dim⁡(Ft)N=P(N). Substitution in the current vacuum-weight formula [F2] gives h(β−n)=an and h(δ−n)=bn. The charges are integral for the screening hypotheses: 2p(β−n)=i−2pn and 2p(δ−n)=2p−2−i−2pn are integers. Thus each composition used in [F4] is defined under [F2].

2.1F2F4step 1.1algebra

Fix n≥0, let t=β−n, so t∗=δ+n, and set w=Q2n+1e(δ−(n+1))α. By [F4] this vector is nonzero in Fδ+n; by [F2] it is singular. Screening commutation preserves its weight, which is bn+1, while the target vacuum in Fδ+n has weight an. Its relative oscillator level is g=bn+1−an=(i+1)(2n+1)>0.

3.1F1F3F6step 2.1algebra

The highest-vector property defines a Verma map A:M(c,an)→Ft sending its top to etα; its image is the stated cyclic module. For a level-g PBW word X, the adjoint identity in [F3] gives ⟨AXvan,w⟩=⟨etα,X∗w⟩=0, because X∗ is a nonempty product of positive modes and each positive mode kills the singular vector w. Nondegeneracy of the pairing makes u↦⟨u,w⟩ a nonzero functional on (Ft)g, so the level-g image is proper. Its domain and target both have dimension P(g) by [F1] and [F6]; hence ker⁡A has a nonzero vector at level g.

4.1F5step 3.1algebra

The kernel of A is a proper graded submodule because its highest vector maps to a nonzero vacuum. By [F5], it lies in the maximal proper submodule J of M(c,an), whose first nonzero level is g and whose grade-g space is one-dimensional. Step 3.1 then implies ker⁡A contains that first singular vector; since this vector generates J, while ker⁡A⊆J, equality follows. Thus the actual cyclic image is L(c,an), with the first character in the Statement by [F5].

5.1F1F2F3F4F5F6step 3.1algebra∎

For n≥1, put t=δ−n, so t∗=β+n. The vector w=Q2ne(β−n)α∈Fβ+n is nonzero by [F4], singular by [F2], and has weight an; the target vacuum weight is bn, so its positive relative level is g=an−bn=2nd. The same adjoint calculation as in step 3.1 makes the level-g Verma-map image proper. Equal level dimensions [F1, F6] give a nonzero kernel vector there. By [F5], the kernel is contained in the first maximal submodule, meets its one-dimensional first grade, and therefore equals it. This proves the second cyclic irreducibility and character formula.

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