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Quasi-primary translation series converges in the Hilbert space

Statement

Let U be a positive-energy unitary Möbius representation with generators L−1,L0,L1 satisfying [L1,L−1]=2L0, [L0,L−1]=L−1, and L−1∗=L1 on smooth vectors. If a is a quasi-primary vector with L0a=da, d∈Z≥0, and L1a=0, then for every smooth function f on S1 the series a(f)=∑n≥0f^−n−dL−1nan!,f^m=∫−ππf(eiϑ)e−imϑdϑ2π, converges absolutely in the Hilbert-space norm.

Facts & Assumptions

Given: A positive-energy unitary Möbius representation with the stated generator conventions, a quasi-primary vector a of weight d∈Z≥0, and a smooth circle function f.

[F1]

The Möbius generators satisfy [L1,L−1]=2L0, [L0,L−1]=L−1, and L−1∗=L1 on smooth vectors (Möbius and conformal nets on the circle).

[F2]

The inner product is positive definite and linear in its first argument (Real and complex inner-product spaces and their induced length).

[F3]

The Hilbert norm is complete, so every norm-Cauchy series converges in the Hilbert space (Hilbert space).

[A1]

The vector satisfies L0a=da and L1a=0, with d∈Z≥0.

Proof

1.1givenF1F3constructalgebra

We first establish the missing domain assertion for the genuine positive-energy Möbius representation in [F1], without assuming finite-dimensional energy eigenspaces. Its rotation subgroup has period 2π, so its spectral projections are Pm=(2π)−1∫02πe−imtU(rt) dt, with Hm=PmH and m∈Z≥0; negative grades are zero. Smooth group vectors are dense: for ξ∈H, integrate U(g)ξ against a smooth compactly supported approximate-identity density on the finite-dimensional Möbius group. Strong continuity gives convergence to ξ; translating the integral transfers every derivative to the smooth density, so these are smooth vectors. Rotation projection preserves smooth vectors: derivatives of U(g)U(rt)ξ=U(rt)U(rt−1grt)ξ are uniformly bounded for t in the compact rotation circle and may be integrated. Hence Em=PmHU∞ is dense in Hm. Rotation covariance of the complexified generators on smooth vectors gives L1Em⊂Em−1 and L−1Em⊂Em+1. All bracket and adjoint calculations in the next step take place first on these actual smooth vectors.

2.1givenF1F2F3step 1.1algebra

On E0, positivity of energy gives L1=0, and the adjoint identity and [L1,L−1]=2L0 then give L−1=0. Inductively, if L−1:Em−1→Hm has norm at most m(m−1), then, for v∈Em, testing L1v∈Hm−1 against the dense Em−1 and using the adjoint identity gives ∥L1v∥≤m(m−1)∥v∥. Consequently ∥L−1v∥2=∥L1v∥2+2m∥v∥2≤m(m+1)∥v∥2. This proves the induction for every m. Thus both modes extend boundedly on each energy space, with these same bounds, and L0 acts there as m. These extensions are the actual infinitesimal actions, not arbitrary bounded replacements. For a real Lie algebra element X, its action on smooth vectors is a fixed complex linear combination of these three modes. Approximate any v∈Hm by vj∈Em; the mode bounds make dU(X)vj converge to that same combination of extended modes. The full infinitesimal generator of the strongly continuous one-parameter unitary group is closed: if vj→v and dU(X)vj→w, pass to the limit in U(exp⁡(tX))vj−vj=∫0tU(exp⁡(sX))dU(X)vj ds and differentiate at zero. Thus v is in its domain with that action. The extensions preserve finite energy, so all finite products of real generators are defined on Hfin. Smooth-vector bracket and adjoint identities extend to fixed finite grades by the bounded estimates.

3.1givenF1F3step 2.1constructalgebra

These domain assertions imply actual group smoothness. Fix a real basis X1,X2,X3 of the Möbius Lie algebra. Each dU(Xi) is a fixed sum of the three energy modes. The preceding bounds imply that, for v∈Hm, every word of length ℓ in this real basis has norm at most Cℓ(m+ℓ+1)!(m+1)!∥v∥, for one constant C independent of m,ℓ: each mode changes energy by at most one and its norm at grade r is at most r+1. For each real generator, its exponential series therefore converges, together with every derivative, when ∣t∣<1/C. The integral generator identity from 2.1 and closedness justify termwise differentiation in its graph norm; multiplying the resulting solution by U(exp⁡(−tXi)) shows it equals the actual unitary orbit. More generally the mixed series for U(exp⁡(t1X1))U(exp⁡(t2X2))U(exp⁡(t3X3))v converges absolutely when C∑i∣ti∣<1: grouping terms of total degree ℓ, the factorial denominators give (∑i∣ti∣)ℓ/ℓ!, and the remaining factorial ratio grows only polynomially in ℓ after division by ℓ! for fixed m. The same bound with additional polynomial factors permits every parameter derivative. Repeated use of the one-parameter identity and absolute convergence identifies this series with the actual product orbit. The product of exponentials is a smooth coordinate chart near the group identity, since its differential sends the coordinate basis to X1,X2,X3. Thus every v∈Hm, and hence every finite sum of such vectors, belongs to HU∞. This proof does not use finite multiplicity or a decomposition into irreducible representations.

4.1givenF1A1step 3.1algebra

In particular the vector a∈Hd in the Statement is Möbius smooth, and every L−1na∈Hd+n is smooth. The given eigenvector and lowest-weight equations therefore hold in the common smooth domain, and every use below of commutators or adjoints on descendants is justified by 1.1, 2.1, 3.1. This establishes the domain prerequisite for the original, unchanged quasi-primary series, rather than adding a new smooth-vector hypothesis.

5.1givenF1A1step 4.1algebra

For n≥1, expand L1L−1na by commuting L1 past the n factors L−1. The commutator terms are ∑r=0n−1L−1r(2L0)L−1n−1−ra=2∑j=0n−1(d+j)L−1n−1a=n(2d+n−1)L−1n−1a, because L0L−1ja=(d+j)L−1ja and L1a=0.

6.1givenF1F2A1step 5.1algebra

Using L−1∗=L1 and the linear-first inner-product convention, [F2] gives ∥L−1na∥2=⟨L−1n−1a,L1L−1na⟩=n(2d+n−1)∥L−1n−1a∥2. Iteration yields ∥L−1nan!∥2=(2d)nn!∥a∥2=(2d+n−12d−1)∥a∥2(d≥1), while for d=0 the first recurrence gives L−1a=0 and every positive-degree term vanishes.

7.1F3A1step 6.1algebra∎

For d≥1, the binomial coefficient in 6.1 is bounded by a constant depending on d times (1+n)2d−1, so ∥L−1na/n!∥ grows at most polynomially in n. Repeated integration by parts in the Fourier integral gives ∣f^m∣≤Cf,N(1+∣m∣)−N for every integer N≥0. Choose N>d+1; then the norms of the terms in a(f) have summable upper bounds. Completeness of the Hilbert space implies absolute norm convergence. The d=0 case is a finite sum by 6.1.

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