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Charged rank-one Fock spaces carry a central-charge-one Virasoro action

Statement

For every real p, the operators in the charged rank-one Heisenberg Fock space satisfy [am,an]=mδm+n,0I and the normally ordered modes Ln(p) are a representation of the Virasoro algebra with central charge 1. On the algebraic core,

L0(p)=p22I+∑k≥1kxk∂∂xk,L−1(p)=∑k≥1kxk+1∂∂xk+px1.

Let I be the set of finitely supported sequences u:Z>0→Z≥0, where Z>0={1,2,…}. The monomial ∏k≥1xkuk has oscillator level ∑k≥1kuk and conformal weight p2/2+∑k≥1kuk. For real p, the inner product is positive. Put eu=∏k≥1xkuk∏k≥1kukuk!(u∈I). For k≥1, the closures Ak,A−k in Fp of the polynomial mode restrictions have domains Dom⁡(Ak)={∑ucueu:∑ukuk∣cu∣2<∞},Dom⁡(A−k)={∑ucueu:∑uk(uk+1)∣cu∣2<∞}, with Akeu=kuk eu−δk (zero when uk=0) and A−keu=k(uk+1) eu+δk, where (δk)j=1 if j=k and 0 otherwise. They satisfy Ak∗=A−k and A−k∗=Ak with these Hilbert-space domains. The zero mode a0=pI is bounded self-adjoint for real p.

Statement references

Facts & Assumptions

Given: A real number p and the polynomial core and modes of the charged Heisenberg Fock space.

[F1]

Charged rank-one Heisenberg Fock space fixes a−k=xk, ak=k∂xk, a0=pI, the normal-order convention, and the monomial inner product.

[F2]

Virasoro algebra in the Lm convention uses the bracket [Lm,Ln]=(m−n)Lm+n+m3−m12δm+n,0C.

Proof

Given: p∈R.

1.1givenF1algebra

Multiplication and differentiation give [ak,a−ℓ]=kδkℓI for k,ℓ≥1, while all two multiplication operators commute, all two derivative operators commute, and a0=pI commutes with every mode. Therefore [am,an]=mδm+n,0I for all integers m,n.

2.1F1step 1.1algebra

For fixed n and a fixed polynomial, terms in ∑j:ajan−j: with a sufficiently large positive index kill that polynomial; terms with two negative indices have j+(n−j)=n and hence occur only finitely many times. Thus Ln(p) is well defined on P.

3.1F1step 1.1step 2.1algebra

In the commutator [Lm(p),an], the identity [AB,C]=A[B,C]+[A,C]B leaves only the summands whose one index is −n. Their equal contributions and the prefactor 1/2 give [Lm(p),an]=−nam+n.

4.1step 1.1step 3.1algebra

Set Cm,n=[Lm(p),Ln(p)]−(m−n)Lm+n(p). The Jacobi identity and step 3.1 show [Cm,n,ak]=0 for every k. An operator on P commuting with every multiplication xj and every derivative j∂xj is scalar: its value on 1 is killed by each derivative, so is constant, and commutation with multiplication determines its value on every monomial. Hence each Cm,n is scalar. Since Lj(p) has oscillator degree −j, this scalar is zero unless m+n=0.

5.1F2step 3.1step 4.1algebra

For m>0, normal ordering gives L−m(p)1=pxm+12∑k=1m−1xkxm−k, Lm(p)1=0, and L0(p)1=(p2/2)1. Using step 3.1, [Lm(p),L−m(p)]1=(mp2+12∑k=1m−1k(m−k))1. Subtracting 2mL0(p)1=mp21 leaves 12∑k=1m−1k(m−k)1=(m3−m)1/12. Antisymmetry gives the same polynomial for negative m, and m=0 gives zero. This proves the Virasoro bracket with central charge 1 in [F2]'s convention.

6.1F1step 1.1step 5.1algebra

Direct evaluation of the normally ordered sums for n=0,−1 gives the two displayed formulas. For monomials, the inner product in [F1] gives ⟨akf,g⟩=⟨f,a−kg⟩ and ⟨a−kf,g⟩=⟨f,akg⟩ for every k≥1. Since each normally ordered sum acts finitely on a polynomial, termwise adjunction gives ⟨Ln(p)f,g⟩=⟨f,L−n(p)g⟩ for f,g∈P. These are algebraic-core identities for the quadratic modes. The weight formula follows by applying the Euler operator in L0(p) to each monomial.

7.1F1step 1.1algebra∎

Let eu be the normalized monomial basis in the Statement. On this orthonormal basis, the polynomial restrictions act by the displayed weighted shifts. If a sequence and its weighted-shift images converge in Fp, coordinatewise convergence gives the same shift formulas for the limits, so the maximal weighted shifts are closed. Truncation to finitely many basis vectors converges in each graph norm, hence these are the closures of the polynomial restrictions. For v=∑ucueu, the adjoint coefficient identity against each eu forces Ak∗v to have the coefficients of A−kv. Because finite-support vectors are graph-dense, this identity extends to the full domain exactly when the forced coefficient sequence is square-summable, which is equivalent to ∑uk(uk+1)∣cu∣2<∞. Reversing the roles gives A−k∗=Ak. The zero mode is the bounded self-adjoint scalar pI because p∈R.

Remarks

The charge p is real in this lemma because the stated positive inner product makes a0=pI self-adjoint. The algebraic formulas also define representations for complex p, but that larger family is not asserted to be unitary.

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