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Nilpotent parts on a joint cyclic subspace give finite logarithmic dilation factors
Statement
Let be a complex vector space, let be commuting linear maps, and let satisfy and for positive integers . Let . Let be simply connected open sets, with chosen holomorphic logarithms and .
The span
is finite dimensional and invariant under and . On , define
Then
For every linear functional , the normalized matrix coefficient is the finite polynomial
Thus the nilpotent generator parts supply possible logarithmic terms; a chosen pairing may annihilate their positive-degree coefficients. Under a Euclidean loop about the origin, changes by and by , so the continued dilation is
Single-valuedness therefore requires a separate condition on the paired fields and matrix coefficients.
Facts & Assumptions
Given: The vector space , commuting endomorphisms , a vector with the stated nilpotence orders, scalars , and the two chosen logarithm branches.
The positive integers satisfy and .
The branches are holomorphic logarithms on the specified simply connected subsets of ; on the Euclidean locus , continuation around zero changes the branches by and , respectively.
Proof
Since and commute, every with equals , and every one with equals . Thus is spanned by at most vectors. Applying or to its spanning vectors either gives another listed vector or zero, so is invariant.
On , the restrictions of and are nilpotent and commute. Expanding the two matrix exponentials and using the binomial identity for commuting operators gives . Every term with or vanishes by [A1], so the product of exponential series is exactly the displayed finite double sum. Applying gives the normalized matrix coefficient.
Continuing the two logarithms by the changes in [A2] multiplies the first exponential by and the second by . The factors commute with each other and with , yielding the stated continuation formula.
Dependency tree · 0 levels
Nothing. This result depends on no other item in the library.