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LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-11-04 (gpt-6-luna)
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Extension phases with period 2πi are independent exactly at integral level

Statement

Let B be a nonempty set of boundary data. For each b∈B, let Eb be a nonempty set of admissible extensions and let Γb:Eb→iR be their imaginary-valued action term. Assume every extension difference is an integral period, meaning Γb(e1)−Γb(e0)∈2πiZ for every b∈B and e0,e1∈Eb. Assume also that some pair e0,e1∈Eb has difference 2πi. For real k, define the unit circle U(1):={u∈C:∣u∣=1} and the phase Wb,k(e)=exp⁡(−kΓb(e))∈U(1). Then Wb,k(e) is independent of the chosen extension for every b if and only if k∈Z.

Facts & Assumptions

Given: The nonempty extension sets Eb, the imaginary-valued functions Γb, and a real coefficient k as in the Statement.

[A1]

For every boundary datum and every pair of its admissible extensions, the difference of the two Γb values is in 2πiZ.

[A2]

At least one admissible pair has Γb(e1)−Γb(e0)=2πi.

Proof

1.1givenA1algebra

Suppose k∈Z. For any b∈B and e0,e1∈Eb, [A1] gives an integer n with Γb(e1)−Γb(e0)=2πin. Therefore Wb,k(e1)Wb,k(e0)=exp⁡ ⁣(−k(Γb(e1)−Γb(e0)))=exp⁡(−2πikn)=1. Thus the phase is independent of extension for every boundary datum.

2.1givenA2algebra∎

Conversely, suppose the phase is independent of extension for every boundary datum. Choose the pair in [A2]. Equality of its phases gives exp⁡(−2πik)=1. Since k is real, this is equivalent to cos⁡(2πk)=1 and sin⁡(2πk)=0, hence to k∈Z.

Remarks

This lemma proves the level criterion only from the stated period-group hypotheses. In a compact WZW model those period hypotheses are part of the chosen normalization of the Wess–Zumino datum; the lemma does not prove that such a datum exists for every Lie group.

Dependency tree · 0 levels

Nothing. This result depends on no other item in the library.

Sources