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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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Continuous second partials of a scalar potential commute

Statement

Let U⊆Rn be open and let ϕ:U→R have continuous second partial derivatives. Then

∂j∂iϕ(x)=∂i∂jϕ(x)

for every x∈U and every pair of coordinate indices i,j.

Facts & Assumptions

Given: The open set, function, point, and indices in the Statement.

[L1]

The coordinate partial derivative ∂iϕ(x) is the derivative at zero of t↦ϕ(x+tei) (Directional derivatives and partial derivatives of a map U⊆Rm→Rn).

[L2]

A real function continuous on [a,b] and differentiable on (a,b) has an interior point c with f(b)−f(a)=f′(c)(b−a) (The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a)).

Proof

technique · direct
1.1givencases

If i=j, the displayed equality has identical sides. Assume henceforth that i≠j. Since U is open, choose a ball about x contained in U, and choose nonzero h,k small enough that the coordinate rectangle with vertices x, x+hei, x+kej, and x+hei+kej lies in that ball.

2.1step 1.1L1L2algebra

Divide the rectangular difference R(h,k):=ϕ(x+hei+kej)−ϕ(x+hei)−ϕ(x+kej)+ϕ(x) by hk. Apply [L2] on the ordered endpoint intervals first in direction i and then in direction j; this covers either sign of h and k. Using [L1], there are points ξ and η inside the corresponding coordinate intervals such that R(h,k)hk=∂j∂iϕ(x+ξei+ηej).

2.2step 1.1L1L2algebra

Applying [L2] in the opposite order gives interior points ξ′ and η′ such that the same quotient equals R(h,k)hk=∂i∂jϕ(x+ξ′ei+η′ej).

3.1step 2.1step 2.2given

Let h and k tend to zero through nonzero values. All four intermediate displacements tend to zero. Continuity of the two second partials in steps 2.1 and 2.2 therefore gives ∂j∂iϕ(x)=∂i∂jϕ(x).

4.1step 1.1step 3.1∎

Together with the i=j case in step 1.1, this proves the assertion for every pair of indices.

Depends on

Dependency tree · 2 levels

Sources