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Iterates of the stroboscopic map, and equilibria as fixed points

Statement

Retain all notation and hypotheses of The stroboscopic (time-P) map of a P-periodic first-order system: U⊆Rn is open, P>0, and F:R×U→Rn is continuous, locally Lipschitz in the state variable, and P-periodic.

  1. If z∈DP and θP(z)∈DP, then [0,2P]⊆Jz and

θP(θP(z))=xz(2P).

  1. If z∗∈U satisfies F(t,z∗)=0 for every t∈R, then z∗∈DP and θP(z∗)=z∗.

Facts & Assumptions

Given: The hypotheses of The stroboscopic (time-P) map of a P-periodic first-order system: an open U⊆Rn, a number P>0, and a continuous map F:R×U→Rn, locally Lipschitz in the state variable and P-periodic; for clause 1 a point z∈DP with θP(z)∈DP; for clause 2 a point z∗∈U with F(t,z∗)=0 for every t.

[F1]

Each initial value problem x′=F(t,x), x(t0)=x0 satisfies the Picard-Lindelof hypotheses, so it has a unique maximal solution whose domain is an open interval containing t0, and every other solution through the same data is a restriction of it (Every Picard–Lindelöf initial value problem has one maximal solution on an open interval, Extensions, maximal solutions, maximal intervals, and global solutions).

[F2]

The stroboscopic map satisfies θP(w)=xw(P) for w∈DP, and DP={w∈U:[0,P]⊆Jw} (The stroboscopic (time-P) map of a P-periodic first-order system).

[F3]

If two locally unique solutions of the same continuous equation are defined on adjacent intervals, agree at the common endpoint, and solve the equation there, their piecewise union is a solution on the union interval (Locally unique ODE solutions agree on overlaps and glue across a common endpoint).

[F4]

The right-hand side is P-periodic, so F(t+P,x)=F(t,x) for all (t,x) (The stroboscopic (time-P) map of a P-periodic first-order system).

Proof

technique · direct
1.1F2givenconstruct

Put w:=θP(z)=xz(P), a point of DP by hypothesis, and let xw:Jw→U be the maximal solution of x′=F(t,x), x(0)=w; by [F2] the interval Jw contains [0,P]. Define y:[0,2P]→U by y(t):=xz(t) for t∈[0,P] and y(t):=xw(t−P) for t∈[P,2P].

2.1step 1.1F3F4algebra

The curve y is well defined and continuous: at the common point P both formulas give y(P)=xz(P)=w=xw(0). On [0,P] it solves the system by definition of xz. On [P,2P], writing s=t−P, one has y′(t)=xw′(s)=F(s,xw(s))=F(s+P,xw(s))=F(t,y(t)) by P-periodicity [F4]. At t=P the one-sided derivatives are y′(P−)=F(P,w) and y′(P+)=F(0,w), equal by [F4]; hence y′(P)=F(P,y(P)). The domain-relative endpoint derivatives of the ODE solution definition and the gluing fact [F3] therefore make y a solution on [0,2P].

3.1step 1.1step 2.1F1F2algebra

The curve y satisfies y(0)=xz(0)=z, so y is a solution of the initial value problem with data (0,z) on [0,2P]. By the uniqueness clause of [F1] every solution through (0,z) is a restriction of the maximal solution xz, so [0,2P]⊆Jz and y=xz∣[0,2P]. In particular xz(2P)=y(2P)=xw(P)=θP(w)=θP(θP(z)).

4.1F1F2given∎

For clause 2, the constant curve c(t):=z∗ is a solution of the system on R because c′(t)=0=F(t,c(t)); it satisfies c(0)=z∗, so by the uniqueness clause of [F1] it is a restriction of xz∗. Hence [0,P]⊆Jz∗, that is z∗∈DP, and θP(z∗)=xz∗(P)=c(P)=z∗.

Remarks

  • Clause 1 is the precise sense in which iterating a stroboscopic map follows the continuous solution across successive periods: each iterate requires the previous value to lie in DP again, and then the iterate equals the value of the same maximal solution at the corresponding multiple of P. The identity extends by induction to k-fold iterates as long as every intermediate value lies in DP.

  • No claim is made that DP is nonempty, open, or forward invariant, or that θP has periodic points. Clause 2 shows only that every equilibrium of the P-periodic vector field gives a fixed point of θP with domain membership.

Depends on

Dependency tree · 2 levels

Sources