Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Cw homotopy equivalence inclusions are strong deformation retracts

Statement

If A⊂X is a CW subcomplex and its inclusion is a homotopy equivalence, then X strongly deformation retracts onto A. Moreover, if (Y,B) is a CW pair and u0,u1:B→Z are homotopic, then the adjunction spaces Z∪u0Y and Z∪u1Y are homotopy equivalent relative to their common subspace Z.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

If (X,A) is a relative CW complex, then A↪X has the homotopy extension property; in particular it is a cofibration. (Relative CW inclusions are cofibrations)

Proof

1.1F1given

First prove the relative inverse assertion: if f:(X,A)→(Y,A) is a homotopy equivalence, equals the identity on A, and both inclusions have HEP, let g be an inverse and ht:gf≃idX. Extend ht∣A over Y by HEP, starting at g, to obtain gt with g1∣A=id. CW inclusions have the needed HEP by F1.

2.1F1step 1.1

Concatenate the homotopy g1−2tf for 0≤t≤1/2 with h2t−1 for 1/2≤t≤1. It runs from g1f to the identity, and on A is a path followed by its reverse. Such a loop contracts relative to its endpoints: if its first-half path is γ, replace γ(min⁡(2t,2−2t)) by γ((1−u)min⁡(2t,2−2t)). HEP for (X×I,A×I) extends this homotopy of homotopies. Following the left, top, and right sides of the parameter square now gives g1f≃idX relative to A. This product HEP follows by taking the product of the HEP retraction X×I→X×{0}∪A×I with the other interval.

3.1step 1.1step 2.1

Repeat the preceding adjustment with g1 and f interchanged, obtaining f1 fixed on A with f1g1≃idY relative to A. Then f1≃f1g1f≃f relative to A, so fg1≃idY relative to A. Apply this result with the map A↪X: its relative inverse is a retraction, and the relative inverse homotopy is precisely a strong deformation retraction. If A is empty, the existence of an inverse forces X empty.

4.1F1algebra∎

For a homotopy U:B×I→Z from u0 to u1, use the common space W=Z∪U(Y×I). The CW prism retraction of Y×I onto Y×{0}∪B×I fixes B×I and descends to a strong deformation retraction of W onto the first adjunction space, fixed on Z. The reversed prism gives the second retraction. These prism retractions can be built cellwise using radial projection of Dr×I onto its bottom and sides; concatenate over dimensions with the CW weak topology, as in the HEP construction. Composing the two inclusions and retractions gives inverse homotopy equivalences relative to Z.

Depends on

Dependency tree · 2 levels

Sources