Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A complete temporal flow identifies smooth Cauchy slices

Physical scope

A differential-topological statement about two smooth Cauchy hypersurfaces and a supplied complete timelike product flow; no field equation or empirical claim is involved.

Statement

Let (M,g,N) be a time-oriented smooth Lorentzian four-manifold. Suppose a smooth three-manifold S0 and a smooth diffeomorphism Ψ:R×S0→M are supplied such that each curve s↦Ψ(s,z) is an inextendible future timelike curve and Ψ(0,z)=z. Let Σ⊂M be a smooth spacelike Cauchy hypersurface, meaning that it is met exactly once by every inextendible causal curve. Then the second-coordinate projection P:=pr⁡S0∘Ψ−1∣Σ:Σ→S0 is a diffeomorphism. In particular, Σ and S0 have the same connectedness and compactness properties.

Facts & Assumptions

Given: A complete timelike product flow Ψ as in the Statement and a smooth spacelike Cauchy hypersurface Σ.

[F1]

The map Ψ is a diffeomorphism, each s-curve is an inextendible future timelike curve, and Ψ(0,z)=z; these are the explicit product-flow hypotheses. In Causal curves, chronological and causal reachability, and inextendibility, timelikeness of a curve requires a future timelike velocity almost everywhere.

[F2]

Spacelike hypersurfaces, acausal sets, Cauchy sets, domains of dependence and Cauchy horizons: a Cauchy hypersurface meets every inextendible causal curve exactly once, and a smooth spacelike hypersurface has a three-dimensional positive-definite tangent space at each point.

[F3]

The smooth inverse function theorem on manifolds: a smooth map with an isomorphism as differential at a point restricts to a diffeomorphism on suitable open neighborhoods.

[F4]

Write V(s,z)=dΨ(s,z)(∂s). It is nonzero because dΨ is invertible. For each fixed z, the smooth function s↦g(V(s,z),V(s,z)) is negative almost everywhere by [F1], hence is nonpositive everywhere: a positive value would, by continuity, give a positive value on an interval of positive measure. Thus every nonzero vector in the orbit tangent line has nonpositive squared norm, whereas [F2] gives positive squared norm for every nonzero vector tangent to Σ. Their intersection is therefore 0, even at an exceptional null orbit tangent.

Proof

Given: [F1]–[F4].

1.1F1F2givenconstruct

For each z∈S0, the orbit s↦Ψ(s,z) is an inextendible timelike curve, so [F2] says it meets Σ in exactly one point. Define P(p) by writing Ψ−1(p)=(s,z) and setting P(p)=z. Every z occurs because its orbit meets Σ, and if P(p)=P(q) then p,q lie on the same orbit, which meets Σ only once; hence P is bijective.

1.2F1given

The map P is smooth because it is the restriction of the smooth map pr⁡S0∘Ψ−1 to the embedded submanifold Σ.

1.3F1F2F4givenalgebra

At p=Ψ(s,z)∈Σ, the kernel of d(pr⁡S0∘Ψ−1)p is the one-dimensional tangent to the s-orbit. If v∈TpΣ is in the kernel, then v lies in that orbit tangent line and is tangent to the spacelike hypersurface. By [F4], v=0. Since both tangent spaces have dimension three, dPp:TpΣ→TzS0 is an isomorphism.

2.1F3step 1.1step 1.2step 1.3∎

By [F3], P is a local diffeomorphism at every point. It is already a bijection by step 1.1, so its local smooth inverses agree with the unique set-theoretic inverse P−1 on their domains; these neighborhoods cover S0, proving that P−1 is smooth. Thus P is a diffeomorphism.

Remarks

The proof uses the Cauchy property of Σ to identify each flow orbit once, and spacelikeness to make the projection a local diffeomorphism. It does not assert that an arbitrary continuous Cauchy set is smoothly diffeomorphic to a chosen slice.

Depends on

Dependency tree · 2 levels

Sources