How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A complete temporal flow identifies smooth Cauchy slices
A differential-topological statement about two smooth Cauchy hypersurfaces and a supplied complete timelike product flow; no field equation or empirical claim is involved.
Statement
Let be a time-oriented smooth Lorentzian four-manifold. Suppose a smooth three-manifold and a smooth diffeomorphism are supplied such that each curve is an inextendible future timelike curve and . Let be a smooth spacelike Cauchy hypersurface, meaning that it is met exactly once by every inextendible causal curve. Then the second-coordinate projection is a diffeomorphism. In particular, and have the same connectedness and compactness properties.
Statement references
Spacelike hypersurfaces, acausal sets, Cauchy sets, domains of dependence and Cauchy horizons
Causal curves, chronological and causal reachability, and inextendibility
Diffeomorphisms and local diffeomorphisms of manifolds
Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model
Facts & Assumptions
Given: A complete timelike product flow as in the Statement and a smooth spacelike Cauchy hypersurface .
The map is a diffeomorphism, each -curve is an inextendible future timelike curve, and ; these are the explicit product-flow hypotheses. In Causal curves, chronological and causal reachability, and inextendibility, timelikeness of a curve requires a future timelike velocity almost everywhere.
Spacelike hypersurfaces, acausal sets, Cauchy sets, domains of dependence and Cauchy horizons: a Cauchy hypersurface meets every inextendible causal curve exactly once, and a smooth spacelike hypersurface has a three-dimensional positive-definite tangent space at each point.
The smooth inverse function theorem on manifolds: a smooth map with an isomorphism as differential at a point restricts to a diffeomorphism on suitable open neighborhoods.
Write . It is nonzero because is invertible. For each fixed , the smooth function is negative almost everywhere by [F1], hence is nonpositive everywhere: a positive value would, by continuity, give a positive value on an interval of positive measure. Thus every nonzero vector in the orbit tangent line has nonpositive squared norm, whereas [F2] gives positive squared norm for every nonzero vector tangent to . Their intersection is therefore , even at an exceptional null orbit tangent.
Proof
Given: [F1]–[F4].
For each , the orbit is an inextendible timelike curve, so [F2] says it meets in exactly one point. Define by writing and setting . Every occurs because its orbit meets , and if then lie on the same orbit, which meets only once; hence is bijective.
The map is smooth because it is the restriction of the smooth map to the embedded submanifold .
At , the kernel of is the one-dimensional tangent to the -orbit. If is in the kernel, then lies in that orbit tangent line and is tangent to the spacelike hypersurface. By [F4], . Since both tangent spaces have dimension three, is an isomorphism.
By [F3], is a local diffeomorphism at every point. It is already a bijection by step 1.1, so its local smooth inverses agree with the unique set-theoretic inverse on their domains; these neighborhoods cover , proving that is smooth. Thus is a diffeomorphism.
Remarks
The proof uses the Cauchy property of to identify each flow orbit once, and spacelikeness to make the projection a local diffeomorphism. It does not assert that an arbitrary continuous Cauchy set is smoothly diffeomorphic to a chosen slice.