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Exact sequence for smooth Deligne cohomology

Statement

Assume full AC, fix a good cover as in Smooth Deligne cohomology model, and assume the comparison input of Good-cover Cech-to-singular comparison input. For every k≥1, the Deligne hypercohomology group has natural maps a, I, and R, and the sequence Hk−1(M;Z)⟶HdRk−1(M;R)→aH^Delk(M;Z)→(I,R)Hk(M;Z)×Hk(M;R)Ωclk(M)⟶0 is exact. The fiber product consists of pairs (c,ω) satisfying cR=[ω]dR; every such ω has integral periods, so the last factor may equivalently be written ΩZk(M).

Facts & Assumptions

Given: Full AC, a finite-dimensional Hausdorff second-countable smooth manifold without boundary, a good cover and its subordinate partition of unity, and the comparison input of Good-cover Cech-to-singular comparison input.

[F1]

Smooth Deligne cohomology model defines the Deligne complex as the shifted cone of Z⊕σ≥kΩ∙→Ω∙, (z,α)↦z−α, equivalently the truncated complex Z→Ω0→⋯→Ωk−1.

[F2]

Good-cover Cech-to-singular comparison input supplies acyclicity on each nonempty finite intersection for the constant integer sheaf and every smooth-form sheaf. The acyclic-cover clause of Acyclic directions of the Čech–Godement double complex makes both augmentations of the Cech–Godement double complex quasi-isomorphisms; composing one with the inverse of the other gives the natural comparison of Canonical map from fixed-cover Čech to sheaf cohomology. Applying this termwise and eliminating the acyclic mapping-cone rows on each finite total diagonal identifies the Cech total complex with derived global sections of the bounded Deligne complex; the alternating fixed-cover total differential is the one defined in Fixed-cover Čech cohomology.

[F3]

The de Rham theorem identifies real de Rham cohomology with real singular cohomology under ACω, implied by full AC.

[F4]

The cone long exact sequence gives the long exact cohomology sequence of the shifted cone triangle, after cochain complexes are reindexed as chain complexes.

[F5]

Good-cover Cech-to-singular comparison input identifies the constant-integer Cech groups appearing in the cone sequence with ordinary singular cohomology, naturally under the stated refinements.

Proof

1.1F1F2F4given

Put Dk=Cone⁡(f)[−1], where f:Z⊕σ≥kΩ∙→Ω∙ sends (z,α) to z−α, as in [F1]. The cone long exact sequence [F4], applied after the Cech-to-sheaf comparison [F2], gives a long exact hypercohomology sequence. Its relevant terms are Hk−1(Z⊕σ≥kΩ∙)→Hk−1(Ω∙)→Hk(Dk)→Hk(Z⊕σ≥kΩ∙)→Hk(Ω∙).

1.2F1F2algebra

For each form degree j, the Cech row Cˇ∙(U,Ωj) has contraction in positive Cech degrees (hc)i0…ip−1=∑iρicii0…ip−1, where (ρi) is the subordinate partition of unity in [F1]. Local finiteness makes the sum smooth and the support condition lets each summand extend by zero; the alternating Cech formula gives δh+hδ=1 for p>0. Consequently the Cech total complex for the full Ω∙ has the same cohomology as its global-section de Rham complex, namely HdR∗(M;R). For σ≥kΩ∙, all total terms below degree k vanish; in degree k the only term is Cˇ0(U,Ωk), whose cocycles are global closed k-forms and which has no degree-(k−1) boundaries. Its hypercohomology is therefore Ωclk(M) in degree k and zero below.

2.1F1F2F3F5step 1.1step 1.2

The comparison input [F5] identifies the constant-integer Cech groups in step 1.1 with ordinary singular cohomology; [F3] identifies the form-complex groups with real singular cohomology. The map Hk−1(M;Z)→HdRk−1(M;R) is coefficient inclusion followed by de Rham, and the final map sends (c,ω) to cR−[ω]. Thus the long exact sequence becomes Hk−1(M;Z)→HdRk−1(M;R)→aH^Delk(M;Z)→(I,R)Hk(M;Z)⊕Ωclk(M)→(c,ω)↦cR−[ω]Hk(M;R). The middle maps are induced by the cone projections, with the sign convention of [F1]. Exactness at every displayed term follows from the long exact sequence.

3.1F3step 2.1∎

The kernel at (I,R) in step 2.1 is exactly the fiber product in the Statement; exactness of that long exact sequence makes (I,R) surjective onto it. If (c,ω) lies in the fiber product, then [ω]=cR; for every smooth integral k-cycle z, de Rham evaluation gives ∫zω=⟨c,z⟩∈Z. Hence ω∈ΩZk(M), so the fiber product is unchanged when the last factor is written with integral-period forms. Exactness at the earlier terms, including the kernel of a, was already established in step 2.1.

Depends on

Dependency tree · 2 levels

Sources