Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passverified 2026-11-05 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Relative disk area is invariant under relative homotopy

Statement

Let (M,ω) be symplectic and fix a stable nodal disk domain with boundary arcs labeled by compact Lagrangians L0,…,Lk. If two smooth componentwise maps u0,u1 are related by a smooth componentwise homotopy that preserves the markings, node matching, boundary labels, and fixed combinatorial domain, then their total symplectic areas agree. Here such a homotopy is a collection of smooth maps UC:C×[0,1]→M, one for each normalized component C, with endpoints u0,C,u1,C, whose boundary segments remain in their fixed Lagrangian labels and whose values match at both branches of every node for every parameter. Thus for every componentwise relative-homotopy class β on this fixed nodal domain, Eω(β)=∑C∫CuC∗ω is well-defined. No identification of classes across different combinatorial domains is asserted by this lemma.

Facts & Assumptions

Given: The stable-disk data and a componentwise relative homotopy as in the statement.

[F1]

Stable J-holomorphic disks with boundary markings: a fixed domain has finitely many normalized disk and sphere components; each disk boundary arc has a fixed Lagrangian label, sphere components are closed, and node branches match under evaluation.

[F2]

Relatively spin Lagrangian data: each boundary label is Lagrangian, so its inclusion i satisfies i∗ω=0.

[F3]

Symplectic and almost-complex curve data: the symplectic form is closed, dω=0.

Proof

1.1givenF1F3algebraconstruct

For one normalized component C, write UC,t=UC(⋅,t), βt=UC,t∗ω, and define αt∈Ω1(C) by αt(v)=ω(dUC(∂t),dUC(v)). The pullback UC∗ω is closed by [F3]; writing it as βt+dt∧αt gives ∂tβt=dCαt in local coordinates. To integrate dCαt, use the following local compact-surface calculation. Cover compact oriented C by finitely many oriented interior charts and, when ∂C≠∅, boundary charts to the half-plane y≥0. Euclidean bump functions supported in these charts, normalized by their finite positive sum, give a finite smooth partition of unity. For each compactly supported chart form η=P dx+Q dy, the interior formula ∫R2dη=0 follows by integrating ∂xQ−∂yP and using compact support; in a boundary chart, with outward-normal-first boundary orientation, ∫y≥0dη=∫y=0P(x,0) dx by the same one-variable fundamental theorem of calculus. Summing the localized identities proves ∫Cdα=∫∂Cα for disk components and ∫Cdα=0 for closed sphere components. Differentiation under the integral on compact C now gives ∫Cu1,C∗ω−∫Cu0,C∗ω=∫01∫∂Cαt dt. This finite-chart proof uses no countable-choice assumption and applies to the full components, without deleting node markings.

2.1F1F2step 1.1algebra∎

On each boundary segment of a disk component, UC maps the swept segment into its fixed Lagrangian Li. Both dUC(∂t) and dUC(v) for a boundary tangent v therefore lie in TLi, so αt(v)=0 by [F2]. Finitely many segment endpoints contribute no boundary integral, and closed sphere components have no boundary. The area change in step 1.1 is consequently zero on every normalized component; summing over the finite normalization from [F1] proves equality of total areas. Node matching keeps the homotopy a homotopy of the specified nodal maps, but no node-boundary cancellation is needed.

Depends on

Dependency tree · 2 levels

Sources