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A nonvanishing holomorphic function on a disc has a holomorphic logarithm
Statement
If is nowhere zero and holomorphic on a disc, then there is a holomorphic on that disc with .
Precisely, if with and is holomorphic and nowhere zero, then there is a holomorphic function satisfying for every .
Facts & Assumptions
Given: A disc with and a nowhere-zero holomorphic function on it. It is nonempty since it contains . For each in it, and imply by the triangle inequality, so the disc is open in . For and the triangle inequality gives , so every segment between two points of the disc stays in it. By affine-segment and openness transport in The complex coordinate isometry transports topology and affine segments, its coordinate image is a convex open subset of in A convex subset of contains every line segment between two of its points, hence star-shaped at in Star-shaped open subsets of Euclidean space. Each coordinate segment is a continuous path by [L4]; composing it with the coordinate homeomorphism inverse gives a continuous path in the disc. Thus the disc is path connected, hence connected by [L4]; together with nonemptiness and openness this makes it a complex domain in A complex domain is a nonempty connected open subset of . Also is itself holomorphic on the disc, because a holomorphic function has complex derivatives of all orders locally (All higher complex derivatives exist and satisfy Cauchy's integral formula on an interior circle), so the quotient rule makes holomorphic there, being nowhere zero (Linearity, product, reciprocal, and quotient rules for complex derivatives); and the complex chain rule, the derivative of , and the exponential addition law are supplied by The chain rule for complex derivatives, The complex exponential is entire and its complex derivative is itself, and , and the complex exponential extends the real exponential.
Every holomorphic function on an open set star-shaped with respect to has a primitive there (Every holomorphic function on a star-shaped domain has a primitive).
A holomorphic function whose derivative vanishes everywhere on a complex domain is constant (A holomorphic function with zero derivative on a domain is constant).
For every nonzero complex number , the solutions of are exactly with (All logarithms of are , ).
A segment that lies in a subset is a continuous path in , and a path-connected subset of a topological space is a connected subset (A finite concatenation of straight segments in is a continuous path, Every path-connected space is connected, and every path component lies inside a component, claim 2).
Proof
By the star-shapedness in the Given and [L1], has a holomorphic primitive on the disc. Put ; then and .
The complex product and chain rules give , so, the disc being a complex domain by [L4], [L2] makes constant; its value at is .
Since , choose by [L3] a complex number with , and set .
The exponential addition law and step 2.1 give throughout the disc, so is the required holomorphic logarithm.
Depends on
Every holomorphic function on a star-shaped domain has a primitive
A complex domain is a nonempty connected open subset of
Star-shaped open subsets of Euclidean space
A convex subset of contains every line segment between two of its points
The complex coordinate isometry transports topology and affine segments
All higher complex derivatives exist and satisfy Cauchy's integral formula on an interior circle
Linearity, product, reciprocal, and quotient rules for complex derivatives
The chain rule for complex derivatives
The complex exponential is entire and its complex derivative is itself
, and the complex exponential extends the real exponential
A holomorphic function with zero derivative on a domain is constant
All logarithms of are ,
A finite concatenation of straight segments in is a continuous path
Every path-connected space is connected, and every path component lies inside a component