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Minimal Dirac magnetic square and formal Pauli benchmark

Statement

Let m>0 be a particle mass in kilograms, q∈R its charge in coulombs, and A:R3→R3 a smooth spatial vector potential with components in tesla-metres. Use standard Cartesian coordinates xi measured in metres and write ∂i:=∂/∂xi. Let ϵijk be the alternating symbol with ϵ123=1, and sum repeated spatial indices from 1 to 3. Define Bk(x)=ϵkij∂iAj(x) and B=(B1,B2,B3):R3→R3; its smooth components are in tesla.

Let C=Cc∞(R3;C4) be the common invariant test domain. In this item, “common core” refers only to this shared domain of the displayed differential expressions; no operator-theoretic core property for a closure is asserted. Define the dimensionless finite matrices σ1=(0110),σ2=(0−ii0),σ3=(100−1), β=(I200−I2),αi=(0σiσi0),Σi=diag⁡(σi,σi), and use ℏ,c of QFT example units, metric, gauge, and pairing conventions. On C, define πiψ=−iℏ∂iψ−qAiψ,HDψ=c∑i=13αiπiψ+βmc2ψ. These maps preserve C. The components πi have units kg m s−1 and HD has units joules. Define the operator expressions π2ψ:=∑i=13πi(πiψ),(Σ⋅B)ψ:=∑i=13ΣiBiψ. Here [πi,πj]:=πi∘πj−πj∘πi, and HD2 denotes composition on C. On C, the identities are [πi,πj]=iqℏϵijkBk,HD2=m2c4I4+c2(π2−qℏΣ⋅B). The operator K:=π2−qℏΣ⋅B maps C to itself and has units (kg m s−1)2.

For commuting formal indeterminates t,X over R, define the first-order square-root coefficient a by (mc2+taX)2≡m2c4+tc2X(modt2). Comparing the coefficient of tX gives a=1/(2m); substituting K for X gives the formal first-degree correction K/(2m), with no operator square-root assertion. Its spin term is −(q/m)S⋅B, where Si=ℏΣi/2, S=(S1,S2,S3), and (S⋅B)ψ:=∑i=13SiBiψ. The magnetic-moment dot product below uses the same componentwise sum convention.

Under the coefficient convention Hmag=−μmag⋅B and μmag=gs(q/(2m))S, equality of the formal coefficients as a linear function of q gives gs=2 for the minimal tree-level term. Here Hmag has units joules and μmag has units A m2. No magnetic self-adjoint closure, full spectrum, operator square-root theorem, radiative correction, or empirical prediction is asserted.

Facts & Assumptions

Given: Assume m>0, q∈R, smooth A with the component units stated above, and the common invariant test domain C defined in the Statement. Use the finite Dirac matrices and SI constants stated above.

[F2]

QFT example units, metric, gauge, and pairing conventions: c is in metres per second, ℏ is in joule-seconds, q is in coulombs, and spatial Ai is in tesla-metres.

Proof

1.1givenF2algebra

For ψ∈C, expand πiπjψ−πjπiψ. The second derivatives and products AiAj cancel; the remaining derivative terms are iqℏ(∂iAj−∂jAi)ψ=iqℏϵijkBkψ by the stated alternating-symbol and summation conventions. Smoothness of A ensures each multiplication and differentiation maps C to itself.

1.2givenalgebra

In R[X,t]/(t2), the coefficient of tX in (mc2+taX)2 is 2mc2a. The defining identity in the Statement sets this equal to c2, so a=1/(2m) since m>0. Substituting K for X, the spin part of K/(2m) is −qℏΣ⋅B/(2m)=−(q/m)S⋅B.

2.1step 1.1givenalgebra

Direct multiplication of the displayed 2×2 matrices gives σi2=I2, σ1σ2=iσ3, σ2σ3=iσ1, and σ3σ1=iσ2; each reversed product has the opposite sign. Thus σiσj=δijI2+iϵijkσk. Block multiplication gives αiαj=δijI4+iϵijkΣk, αiβ=−βαi, and β2=I4. These fixed constant matrices commute with every πj. Expand (∑iαiπi)2=∑i,jαiαjπiπj. The δij term in the derived block product is the operator π2 defined in the Statement. Its antisymmetric term is i2ϵijkΣk[πi,πj]=−qℏ2ϵijkϵijℓΣkBℓ=−qℏΣ⋅B, because ϵijkϵijℓ=2δkℓ. The cross terms with βmc2 cancel by αiβ+βαi=0, and β2=I4. This proves the displayed square identity on C; no product outside that domain is used.

3.1step 1.2givenalgebra∎

The coefficient of the term linear in q is −(q/m)S⋅B. Equating it with −gs(q/(2m))S⋅B as a formal coefficient identity gives gs=2, including the zero-charge specialization of that identity. This is only a formal lowest-order coefficient comparison, not an operator or empirical conclusion.

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