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Gauge-longitudinal kernel decoupling for explicit tree currents

Statement

Use h=−η=diag⁡(1,−1,−1,−1) from Off-shell free Dirac Ward telescoping and tree currents for contractions: for w∈C4, set wa=∑b=03habwb, and sum repeated component indices over 0,1,2,3. Let p1,p1′,p2,p2′ be future-shell momenta for the same μ>0 convention as that lemma, and suppose k=p1−p1′=p2′−p2. Define J1μ:=uˉ(p1′)γμu(p1),J2ν:=uˉ(p2′)γνu(p2), with the on-shell Dirac equations in Off-shell free Dirac Ward telescoping and tree currents. If a finite rational covariant-gauge kernel changes by ΔDμν(k)=c(k)kμkν, where c(k)∈C is finite at the chosen k, then J1μΔDμν(k)J2ν=0. Likewise, let Ja=uˉ(p′)γau(p) with transfer ℓ=p−p′, or Ja=vˉ(q)γau(p) with transfer ℓ=p+q, under the respective future-shell and Dirac-equation hypotheses of Off-shell free Dirac Ward telescoping and tree currents. If k=ℓ or k=−ℓ, then for ϵ∈C4 and a finite α∈C, the contraction ϵaJa is unchanged by ϵa↦ϵa+αka. These statements concern only the displayed finite tree-current contractions; they assert no gauge independence for arbitrary loop diagrams or renormalization schemes.

Facts & Assumptions

Given: The four future-shell spinors and momenta in the Statement, with transfers k and −k on the two fermion lines.

[F1]

Off-shell free Dirac Ward telescoping and tree currents: for each stated on-shell Dirac current, contraction with its momentum transfer is zero; the proof uses the fixed h=−η slash convention.

[A1]

μ>0; each displayed momentum lies on the future shell h(p,p)=μ2; the two kernel currents' spinors satisfy the positive-energy Dirac equations in the cited tree lemma; k=p1−p1′=p2′−p2; and c(k)∈C is finite at the selected k. In the separate polarization clause, the chosen current satisfies the respective positive- or negative-energy equations of that lemma, its transfer ℓ equals k or −k, and ϵ∈C4 and α∈C are finite data. All contractions use h as specified in the Statement.

Proof

1.1A1F1algebra

The first line has transfer p1−p1′=k, so [F1] gives kμJ1μ=0. The second line has transfer p2−p2′=−k, so (−k)νJ2ν=0, hence kνJ2ν=0.

2.1A1step 1.1algebra

Contracting the longitudinal kernel gives J1μΔDμν(k)J2ν=c(k)(kμJ1μ)(kνJ2ν)=0 by [step 1.1].

3.1A1F1algebra∎

For either polarization-current form in the Statement, [F1] gives ℓaJa=0. Since [A1] requires k=ℓ or k=−ℓ, it follows that kaJa=0. Lowering the shifted polarization with h, the change in its contraction is αkaJa=0. This proves the polarization claim for both explicit current types, including the transfer −k of the second kernel current.

Depends on

Dependency tree · 2 levels

Sources