How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Homotopy invariance of singular cohomology with field coefficients
Statement
Let be a field, let be topological spaces, and let be continuous maps joined by a continuous homotopy . Then for every integer . Consequently every homotopy equivalence induces an isomorphism on singular cohomology with coefficients in .
Facts & Assumptions
Given: A field , spaces , continuous maps , and the homotopy from to .
Singular cochains are homomorphisms on singular chains, their coboundary is positive precomposition with the chain boundary, and cohomology is cocycles modulo coboundaries. Singular cochain complex with coefficients Singular cohomology with coefficients
The prism operator satisfies , with in degree . The singular chain homotopy formula
Proof
Given: The data in the statement.
For , define by , and set . Evaluating the chain identity [F2] on an -chain and using the positive coboundary convention in [F1] gives
For , the first summand is zero because , and the degree-zero case of [F2] gives the same identity.
If is a cocycle, then [F1] gives , so step 1.1 says , a coboundary; hence the induced cohomology classes agree. Negative cohomology groups are zero by [F1]. If has homotopy inverse , apply the equality to and ; functoriality of pullback then makes a two-sided inverse for .