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LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Under countable choice, every regular Lindelöf space is paracompact

Statement

Assume the Axiom of Countable Choice. Every regular Lindelöf topological space is paracompact.

Facts & Assumptions

Given: Countable choice, a regular Lindelöf space X, and an open cover U.

[A1]

Countable choice selects from a countably indexed family of nonempty sets (The Axiom of Countable Choice (ACω)).

Proof

technique · constructive
1.1L1F1construct

The family of all open V for which V‾⊆U for some U∈U covers X by [L1]; by Lindelöfness take a sequence V0,V1,… covering X.

2.1A1step 1.1choose

By [A1], choose Un∈U with Vn‾⊆Un for each n.

3.1step 2.1construct

Put Wn:=Un∖⋃i<nVi‾. Each Wn is open and lies in Un.

4.1step 1.1step 2.1step 3.1

The Wn cover X: if n is the least index with x∈Un, then x∉Vi‾ for i<n, since Vi‾⊆Ui, and hence x∈Wn.

4.2step 3.1

The cover is locally finite: for x∈Vk, the neighbourhood Vk is disjoint from Wn for every n>k, while it can meet only W0,…,Wk.

5.1F1step 3.1step 4.1step 4.2discharge-construct∎

Thus {Wn} is a locally finite open refinement of U, and [F1] proves paracompactness.

Depends on

Dependency tree · 2 levels

Sources