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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
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The interval homotopy operator is coordinate independent

Statement

The interval operator K:Ωk(M×[0,1])→Ωk−1(M) is coordinate independent and maps smooth forms to smooth forms.

Facts & Assumptions

Given: A smooth form ω up to the endpoints of M×[0,1].

[F1]

Integration along the unit interval for a differential form: Let ω∈Ωk(M×[0,1]) be smooth up to the endpoints. For k≥1, its interval integral is the (k−1)-form Kω=∫01βt dt, where ω=αt+dt∧βt and both families are tangential to M. Set K=0 on degree zero and on zero terms. Use the product structure of prop-products-of-smooth-manifolds-have-a-canonical-product-smooth-structure, restricted from M×R. The families are intrinsically αt=it∗ω and βt=it∗(ι∂tω), using def-interior-product-of-a-form-by-a-vector-field; evaluation on tangential tuples and on (∂t,v1,…,vk−1) proves existence and uniqueness of the decomposition. The integral is in the fixed finite-dimensional fibre ⋀k−1Tx∗M. Coefficients have smooth local extensions across endpoints. thm-differentiation-under-the-integral-sign-on-a-compact-rectangle supplies parameter differentiation; coordinate independence and full smoothness are proved in lem-the-interval-homotopy-operator-is-coordinate-independent.

[F2]

Leibniz's rule on a compact rectangle: an interior parameter derivative with a continuous extension may be passed through a Riemann integral: Let a<b and c<d. Suppose g,h:[a,b]×[c,d]→R are continuous and, for every fixed t∈[c,d], the function x↦g(x,t) is differentiable on (a,b) with derivative h(x,t). Define G(x):=∫cdg(x,t) dt. Then G is differentiable on [a,b] as a function on that interval and G′(x)=∫cdh(x,t) dt(x∈[a,b]). At a and b the derivative is relative and one-sided. The derivative hypothesis is imposed only for interior parameter values; continuity of h supplies its endpoint values.

Proof

technique · direct
1.1F1given

The coefficient family βt=it∗(ι∂tω) is intrinsically a form in the fixed fibre at x. A change of coordinates on M multiplies its coefficient vector by the exterior-power transition matrix A(x), which does not depend on t. Finite-dimensional integration gives ∫01A(x)βt(x) dt=A(x)∫01βt(x) dt. Thus the local integral expressions transform as a form.

2.1F1F2step 1.1∎

Fix a smaller closed coordinate rectangle about a point of M. Each coefficient b(x,t) and all its derivatives are continuous on that rectangle times [0,1], by local smoothness up to endpoints. Applying compact-parameter differentiation with the other coordinates fixed gives ∂xj∫01b(x,t) dt=∫01∂xjb(x,t) dt. The right side is jointly continuous, since uniform continuity on the compact rectangle bounds the difference of integrals by the supremum difference of integrands. Repetition for every multi-index proves all coordinate derivatives exist and are continuous. Hence Kω is smooth. For k=0, K=0 is smooth directly.

Source locator

Lee, Introduction to Smooth Manifolds, 2nd ed., Lemma 17.9 and Proposition 17.10, pp.444–445; the proof here computes the product differential directly.

Depends on

Dependency tree · 2 levels

Sources