Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Exact charged scattering Wronskian flux identity

Statement

Let u be any scattering solution as defined on the fixed subextremal electric RN exterior, with real ω>0, real e,Q, unit incoming amplitude, and reflection and transmission coefficients R,T. Then its radial Wronskian flux j:=Im⁡(u‾ ∂r∗u) is constant and ∣R∣2=1−ω−eQ/r+ω∣T∣2. Consequently, if 0<ω<eQ/r+ and T≠0, the reflected radial flux magnitude exceeds the incident radial flux magnitude, since their ratio is ∣R∣2>1. This is conditional on an admitted scattering solution and does not assert its existence, a complex-frequency mode, or a nonlinear instability.

Facts & Assumptions

Given: The charged radial scattering definition, a smooth solution of its radial equation, and its stated incoming, reflected, and ingoing-horizon asymptotics.

[F1]

Massless charged-scalar radial scattering data: r∗ tends to −∞ at the outer root and to +∞ at spatial infinity; the asymptotics are u=e−iΘ+ReiΘ+o(1) with the differentiated phase form at infinity and u=Te−iωHr∗+o(1) at the horizon, where ωH=ω−eQ/r+.

[F2]

Charged radial equation on subextremal electric RN: u′′+K(r)u=0 with real K(r)=(ω−eQ/r)2−f(ℓ(ℓ+1)/r2+f′/r) for every r>r+.

[A1]

M>0, 0<∣Q∣<M, e∈R, and ω>0, so r+>0 and both ω and ωH are real.

Proof

1.1givenF2A1algebra

Differentiate j=Im⁡(u‾ u′). The radial equation gives j′=Im⁡(u′‾u′+u‾ u′′)=Im⁡(∣u′∣2−K∣u∣2)=0, because both terms inside the last imaginary part are real by [F2]. Thus j is constant along the exterior.

2.1givenF1F2A1step 1.1algebra∎

At infinity, Θ′=ω−eQf/r→ω. Substitution of the Definition's differentiated asymptotics into j gives j∞=ω(∣R∣2−1): the incident and reflected diagonal terms are −ω and ω∣R∣2, while the two cross terms have real sum. At the horizon the asymptotics give jH=−ωH∣T∣2. Equating these limits by step 1.1 and dividing by ω>0 proves the identity. If 0<ω<eQ/r+ then ωH<0; when T≠0 the identity yields ∣R∣2=1+(−ωH/ω)∣T∣2>1. The unit incoming and reflected asymptotic flux magnitudes are ω and ω∣R∣2, so the stated radial-flux comparison follows.

Remarks

The flux here is the conserved radial Wronskian flux of the separated classical test-field equation. The identity is a linear fixed-background scattering calculation. It gives no conclusion about field backreaction, quantum pair production, trapping, exponential growth, or nonlinear stability.

Depends on

Dependency tree · 2 levels

Sources