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Reflection positivity passes to a distributional limit

Statement

Let Sλ and S be regulated and limit Schwinger hierarchies for one fixed dimension d≥1. Assume each Sλ is reflection positive on the same positive-time algebra and, for every fixed n and every Φ∈S(Rdn), ⟨Snλ,Φ⟩→⟨Sn,Φ⟩. Then S is reflection positive. Euclidean invariance and permutation symmetry also pass to the limit when the same fixed continuous test transformations preserve those properties at every regulator. These hypotheses yield no clustering or order-uniform growth conclusion.

Facts & Assumptions

Given: A directed regulator set Λ, hierarchies Sλ and S as in the earlier limit-data definition, and the two assumptions in the Statement.

[A1]

Every Sλ is reflection positive on the common positive-time polynomial algebra.

[A2]

For each fixed order n, the distributions Snλ converge pointwise on every fixed test Φ∈S(Rdn) to Sn.

[F1]

The limit-data definition fixes the positive-time algebra, reflection form, Euclidean pullbacks, and permutation action.

Proof

Given: [A1], [A2], [F1].

1.1A1A2F1givenalgebra

For each n≥1, define the product-test map Jn:Sd⊗algn→Sd,n by Jn(f1⊗⋯⊗fn)(x1,…,xn)=∏i=1nfi(xi) and linear extension; the product of Schwartz functions is a Schwartz function. Set J0(c)=c and, for a∈Td, define QS(a):=ωS(Θa a). Fix a finite positive-time polynomial a=∑j=0Naj, with each aj a finite sum of degree-j product tests. Expanding concatenation and the moment functional gives the finite sum QSλ(a)=∑j,k=0N⟨Sj+kλ,Jj+k((Θaj)ak)⟩. Every test in this finite sum is fixed independently of λ, so [A2] gives QSλ(a)→QS(a). By [A1], every value QSλ(a) is a nonnegative real number. Since [0,∞) is closed in C, its limit QS(a) is also a nonnegative real number. As a was arbitrary, S is reflection positive.

2.1A2F1step 1.1algebra∎

Fix one Euclidean isometry γ(x)=Rx+b and one order-n test Φ. The pullback Φ↦Φ∘(γ−1)×n is continuous on Schwartz space: the chain rule writes each derivative as a finite linear combination of derivatives of Φ evaluated at the inverse affine image, and each polynomial weight in x becomes a finite sum of polynomial weights in the new variable with fixed coefficients. Thus each transformed Schwartz seminorm is bounded by finitely many original seminorms. If every Snλ is invariant under this fixed pullback, [A2] applied to both Φ and its pullback passes the equality to Sn. A permutation of argument blocks is a coordinate permutation and preserves the same seminorms exactly, so the same limit argument passes permutation symmetry. Step 1.1 uses only a fixed finite number of orders and tests; it supplies neither a uniform-in-n bound nor a limit as a translation parameter tends to infinity, so it proves no order-uniform growth or clustering claim.

Depends on

Dependency tree · 2 levels

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