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The Lie algebra of a Lie subgroup is a Lie subalgebra

Statement

Assume ACω. If i:H→G is a Lie-subgroup inclusion, then

die:Lie⁡(H)=TeH⟶Lie⁡(G)=TeG

is injective and identifies Lie⁡(H) with the Lie subalgebra die(TeH) of Lie⁡(G).

Facts & Assumptions

Given: ACω, a finite-dimensional real Lie group G, and a Lie subgroup i:H→G.

[F1]

A Lie-subgroup inclusion is an injective immersion and a smooth Lie-group homomorphism. Immersed, embedded, and closed Lie subgroups.

[F2]

The differential of an immersion is injective at every point. Immersed, embedded, and closed Lie subgroups.

[F3]

Under ACω, the identity differential of a smooth Lie-group homomorphism is linear and bracket preserving. The Axiom of Countable Choice (ACω), Differential of a Lie-group homomorphism is a Lie-algebra homomorphism.

[F4]

A Lie subalgebra is a linear subspace closed under the ambient bracket. Lie subalgebras and ideals.

Proof

technique · identify the tangent algebra with the image of the identity differential
1.1F1F2algebra

Since i is an immersion by [F1], its differential die:TeH→TeG is injective by [F2]. It is therefore a linear isomorphism from TeH onto the linear subspace h:=die(TeH)⊆TeG.

2.1F1F3step 1.1

Because i is also a smooth Lie-group homomorphism, [F3] gives die([X,Y]H)=[dieX,dieY]G for all X,Y∈TeH. Hence the bracket of any two vectors in h again lies in h.

3.1F3F4step 1.1step 2.1∎

Thus h is a bracket-closed linear subspace of TeG and so is a Lie subalgebra by [F4]. Step 1.1 identifies Lie⁡(H) with it, and step 2.1 shows that this identification respects Lie brackets. This includes the zero-dimensional and full-dimensional cases. The only choice used is the stated ACω inherited by [F3].

Depends on

Dependency tree · 2 levels

Sources