Alphabeta Math
Physics theoremStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck pendingverified 2026-10-23 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Continuum entropy residual and Newtonian admissibility

Physical scope

Conditional smooth local-equilibrium continuum calculation with positive temperature, the stated local mass and energy-balance hypotheses, and Newtonian/Fourier closure. Entropy production is a pointwise coefficient test, not an empirical validation or a proof of the adopted entropy postulate.

Statement

Assume the complete smooth material, state, contact and mass/momentum/angular-momentum/total-energy balance hypotheses of the local Gibbs-entropy identity, including ACω and positive temperature, as stated in Facts & Assumptions. Use a C2 local state relation e(v,s) with v=1/ρ, T=es(v,s)>0, and p=−ev(v,s). Let σ=−pI3+τ, define Lij=∂xjui, D=(L+LT)/2, θ=tr⁡D, and set G=ρDts+div⁡(q/T)−ρr/T,Dt=∂t+u⋅∇. For the adopted Newtonian/Fourier form τ=2μD0+ζθI3, define D0=D−θI3/3, A:B:=∑i,j=13AijBij for A,B∈R3×3, and ∣D0∣2:=D0:D0=∑i,j=13(D0)ij2. Set sym⁡(K):=(K+KT)/2 and q=−K∇T. The residual is G=2μ∣D0∣2+ζθ2T+(∇T)Tsym⁡(K)∇TT2. At a fixed state, if the algebraic coefficient family is tested for every symmetric D, every g=∇T∈R3, and every T>0, this residual is nonnegative exactly when μ≥0, ζ≥0, and xTsym⁡(K)x≥0 for every x∈R3. These conditions make the adopted closure compatible with the separate continuum entropy inequality. In SI units, G has units W m−3 K−1. The theorem does not derive the balance or entropy postulates, infer material coefficients, or assert empirical validity.

Facts & Assumptions

Given: The smooth material motion and positive-density fields, the C2 state relation, local-equilibrium closure, ACω, and the contact and material-balance assumptions specified below.

[A1]

Single-component nonpolar continuum and material balances: the physical postulate adopts no-source mass conservation, local contact traction σn, linear and angular momentum balances, total-energy balance, and a separate entropy inequality on its smooth positive-density material regions. It does not derive these assumptions. Its current batch-3 carrier and source-backed formulation were inspected, and step1Decision currently reports ready.

[A2]

Local simple-fluid equilibrium and Gibbs closure: at each admissible state, v=1/ρ, e∈C2, T=es>0, and p=−ev; this is an adopted local state relation. The current batch-11 carrier states this relation explicitly.

[A3]

Newtonian stress and Fourier conductive closure: the adopted stress and heat-flux closures are τ=2μD0+ζθI3 and q=−K∇T, with specified state laws and nonnegative μ,ζ,sym⁡K. The current batch-11 carrier states this closure explicitly.

[L1]

Gibbs cancellation and entropy-production identity: under ACω, an open time interval, a bounded C1 material region, a C2 orientation-preserving motion, positive C1 density and state fields with v=1/ρ, T=es>0, p=−ev, a C1 stress split σ=−pI3+τ, the local contact hypothesis, continuity equation, and separate linear/angular-momentum and total-energy integral balances, it concludes σ=σT, ρDte=σ:D−div⁡q+ρr, and the displayed Gibbs residual identity. The complete displayed Gibbs hypotheses remain binding, and its proof step 3.1 supplies time recentering.

[L2]

Newtonian/Fourier dissipation and exact coefficient conditions: for ACω, T>0, symmetric D, arbitrary g∈R3, τ=2μD+λ(tr⁡D)I3, q=−Kg, and ζ=λ+2μ/3, the residual decomposes as (2μ∣D0∣2+ζθ2)/T+gTsym⁡(K)g/T2, and it is nonnegative for all D,g,T iff μ,ζ≥0 and sym⁡(K) is positive semidefinite. The algebraic test and its conditional Gibbs interpretation retain exactly these hypotheses.

[A4]

At a point, the algebraic test varies D and g independently; it is not a claim that every such pair occurs in a particular global solution.

Proof

1.1A1A2A3L1algebra

Under the exact motion, contact, continuity and energy-balance hypotheses in [L1], the Gibbs identity gives G=τ:D/T−q⋅∇T/T2. Substitute the postulated closures from [A3]. Since D=D0+θI3/3, tr⁡D0=0, D0:I3=0, and I3:I3=3, contraction gives τ:D=2μ∣D0∣2+ζθ2. Also −q⋅∇T=(∇T)TK∇T=(∇T)Tsym⁡(K)∇T, because a real scalar quadratic form annihilates the skew-symmetric part. This yields the stated formula.

2.1A1A3L2step 1.1algebra∎

Apply the exact coefficient equivalence [L2] with g=∇T, λ=ζ−2μ/3, and T>0. It gives nonnegativity for every independent local D,g exactly under the three stated conditions. The adopted coefficient range in [A3] satisfies those conditions; thus this closure is consistent with the separately adopted entropy inequality in [A1]. This is a conditional model deduction, not a proof of either physical postulate.

Depends on

Dependency tree · 2 levels

Sources