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Closed RNS Light-Cone Mass Shell and Level Matching

Physical scope

Free flat ten-dimensional closed RNS string, in a nonzero-p^+ light-cone chart and the stated zeta-regularized normal ordering; GSO, BRST, interactions, and higher-genus sewing are excluded.

Statement

For the flat ten-dimensional closed RNS string in light-cone gauge, let NL,NR be the left and right transverse oscillator numbers, and let aNS=1/2, aR=0. In any sector pair (sL,sR)∈{NS,R}2, the two zero-mode constraints give α′M24=NL−asL=NR−asR. Their equality is level matching. This is the free-string formula sector by sector before the chosen GSO combination.

Facts & Assumptions

Given: Let D∈Z>0 and impose the local criticality condition in [F3], with a closed string, p+≠0, p2=−M2, independent chiral modes, and the residual left and right light-cone zero-mode constraints in RNS Transverse Oscillator Fock System.

[F1]

RNS Flat Worldsheet Model: the target metric is Lorentzian and α′ has dimension length squared.

[F2]

RNS Spin Structures and Sectors: each chirality has NS half-integer or R integer fermion modes.

[F3]

RNS Local Central-Charge Cancellation: the local flat RNS central term cancels exactly at D=10.

[F4]

RNS Transverse Oscillator Fock System: there are D−2 transverse modes in each chirality, the closed zero modes are α0μ=α~0μ=α′/2pμ, and each chiral constraint is 12α02+N+AB+AF=0 with the displayed zeta prescription.

[F5]

Hurwitz Zeta Values for RNS Normal Ordering: ζ(−1,1)=−1/12 and ζ(−1,1/2)=1/24.

Proof

1.1givenF3F4F5algebra

By [F3], D=10, hence there are eight transverse bosonic modes per chirality by [F4]. Their vacuum term is AB=4ζ(−1,1)=−1/3 by [F5].

2.1givenF2F4F5step 1.1algebra

For an NS chirality, [F2] gives positive frequencies n+1/2, so AFNS=−4ζ(−1,1/2)=−1/6 by [F4]–[F5]; thus ANS=−1/2 and aNS:=−ANS=1/2. For an R chirality, the positive frequencies are integers, so AFR=−4ζ(−1,1)=+1/3 and AR=0, hence aR=0. R zero modes have frequency zero.

3.1givenF1F4step 2.1algebra

For either chirality, [F4] gives 12α02=α′p2/4=−α′M2/4. Its constraint becomes −α′M2/4+N−as=0, where as is the value from step 2.1. Therefore α′M2/4=N−as separately on the left and right.

4.1givenF2F4step 3.1algebra∎

The same momentum pμ occurs in both closed zero modes by [F4]. Equating the two expressions for α′M2/4 from step 3.1 gives NL−asL=NR−asR, exactly the level-matching condition. No open-string zero-mode normalization or post-GSO restriction has been used.

Remarks

For NS-NS, level matching reads NL−1/2=NR−1/2; for R-R it reads NL=NR. Mixed NS-R and R-NS sectors have the corresponding half-unit shift. The equality is a consequence of the two free closed-string constraints, not modular invariance or an interacting sewing theorem.

Depends on

Dependency tree · 2 levels

Sources