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Polyakov Equations and Virasoro Constraints

Physical scope

Classical local field and metric equations of the free tensile flat-target Polyakov model in a Lorentzian conformal-gauge patch; no quantum Weyl-invariance claim.

Statement

For the postulated free flat Polyakov model on a local conformal-gauge patch with hab=e2ϕdiag⁡(−1,+1), write X˙=∂τX, X′=∂σX, σ±=τ±σ, and ∂±=12(∂τ±∂σ). Define Tab=γab−12habhcdγcd, where γab=∂aX⋅∂bX. Variation of X gives X¨−X′′=0. The metric equation Tab=0 gives T++=T−−=0, equivalently X˙⋅X′=0 and X˙2+X′2=0; these constraints remain imposed after choosing conformal gauge and setting ϕ=0.

Facts & Assumptions

Given: A C2 flat-target configuration X, the adopted Polyakov action, and a local Lorentzian conformal-gauge patch with hab=e2ϕηab and ηab=diag⁡(−1,+1).

[F1]

Flat Bosonic String Model: X maps a two-dimensional Lorentzian worldsheet into R1,D−1 with target metric η=diag⁡(−1,+1,…,+1).

[A1]

Bosonic Polyakov Model: SP=−T2∫−h hab∂aX⋅∂bX d2σ, and h is varied as an auxiliary metric.

[F2]

Conformal Gauge and Residual Symmetry: in the selected patch hab=e2ϕηab, σ±=τ±σ, and ∂±=12(∂τ±∂σ); in two dimensions −h hab=ηab, so the conformal factor drops out of the classical X-equation.

Proof

1.1givenF1A1F2algebra

Varying X in [A1] and integrating by parts against compactly supported variations gives ∂a(−h hab∂bXμ)=0. By [F2], this is ηab∂a∂bXμ=−X¨μ+Xμ′′=0, equivalent to the stated wave equation.

1.2givenF1A1algebra

Varying the inverse metric hab in [A1] gives the coefficient γab−12habhcdγcd, where γab=∂aX⋅∂bX; this is Tab as defined in the Statement. Thus the metric equation is Tab=0; gauge fixing changes its coordinate representation but does not remove this Euler–Lagrange equation.

2.1givenF1step 1.2algebra

In the flat conformal representative ηab=diag⁡(−1,+1), direct substitution into [F1]'s induced-metric expression gives T00=12(X˙2+X′2), T11=12(X˙2+X′2), and T01=X˙⋅X′. Hence Tab=0 is equivalent to X˙2+X′2=0 and X˙⋅X′=0.

3.1F2step 2.1algebra∎

With the light-cone convention in [F2], T++=∂+X⋅∂+X=14(X˙2+X′2+2X˙⋅X′), and T−−=∂−X⋅∂−X=14(X˙2+X′2−2X˙⋅X′). Their vanishing is equivalent to the two equations in step 2.1 by adding and subtracting.

Depends on

Dependency tree · 2 levels

Sources