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Physics theoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passverified 2026-11-04 (gpt-6.1-sol)
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RNS chiral picture-charge selection rule

Physical scope

Formal chiral free-field charge neutrality for a fixed genus-g RNS sector with the stated bosonized background-charge Ward convention; not a superstring measure.

Statement

Fix a closed genus-g RNS worldsheet and one chiral sector with the bosonized background convention of RNS bosonized picture charge convention. Here a scalar-picture eigenoperator O of charge p means an insertion with the constant-shift law O[ϕ+a]=epaO[ϕ] for every scalar constant a, with all other fields fixed. Equivalently, in the split ϕ=ϕ0+ϕ~, O[ϕ]=epϕ0O[ϕ~]; epϕ times shift-invariant derivative or spectator fields is included. This is the scalar-exponent picture convention, not an unspecified total grading involving η,ξ. For a formal chiral correlator with such picture eigenoperators of charges p1,…,pn, a nonzero correlator requires ∑ipi=2g−2. The assertion is conditional on the stated bosonized zero-mode Ward convention and does not define a path-integral measure over moduli.

Facts & Assumptions

Given: A compact connected closed genus-g surface, one fixed RNS chirality, the bosonized curvature coupling and formal zero-mode Ward functional of RNS bosonized picture charge convention. Full AC is assumed as required by the genus and Gauss–Bonnet suppliers.

[F1]

RNS bosonized picture charge convention: for Qϕ=2, the curvature term is Sϕ,curv=−(4π)−1∫R(2)ϕ dA; insertions of epiϕ contribute zero-mode exponent ∑ipi; the formal correlator is neutral only when the total coefficient vanishes.

[F2]
[F3]

Global Gauss-Bonnet for closed oriented surfaces: ∫ΣKh dAh=2πχ(Σ); with the convention R(2)=2Kh fixed in [F1], this gives ∫ΣR(2)dAh=4πχ(Σ). The supplier proof carries full AC.

[A1]

The Axiom of Choice is assumed because [F2] and [F3] require it.

Proof

1.1givenF1F2F3A1algebra

In the zero-mode split ϕ=ϕ0+ϕ~, [F3] and [F2] give the curvature term Sϕ,curv=−28π(4πχ)ϕ0=−χϕ0. Therefore e−Sϕ,curv contributes eχϕ0, and each insertion contributes epiϕ0 by the eigenoperator shift law in the Statement (take a=ϕ0). Their product therefore contributes e(∑ipi)ϕ0, including derivative and spectator factors invariant under that shift. The total coefficient is ∑ipi+χ=∑ipi+2−2g.

2.1F1step 1.1algebra∎

By the neutral zero-mode functional in [F1], a nonzero chiral correlator requires this coefficient to vanish. Solving ∑ipi+2−2g=0 gives ∑ipi=2g−2. The calculation applies independently to the right-moving chiral copy.

Remarks

Picture charge is not beta-gamma ghost number. The result follows from the explicit curvature coupling and neutral zero-mode convention; it neither chooses PCO locations nor constructs vertical chains or a global superstring integration cycle.

Depends on

Dependency tree · 2 levels

Sources