Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-13
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Arc length is invariant under every continuous surjective monotone reparametrization, including pauses and reversal

Statement

Let γ:[a,b]→Rn be a path, and let φ:[c,d]→[a,b] be continuous, surjective, and either nondecreasing or nonincreasing. Then

L[c,d](γ∘φ)=L[a,b](γ).

The equality holds for finite or infinite length. Constant stretches of φ are allowed. If [c,d] is a singleton, surjectivity forces [a,b] to be one as well; if instead [a,b] is a singleton, [c,d] need not be, since a constant map on a nondegenerate interval is continuous, surjective and monotone. In both cases each side of the displayed equality is zero.

Facts & Assumptions

Given: The path γ and reparametrization φ.

[L2]

Arc length is the supremum of polygonal sums and repeated consecutive image points contribute zero (Paths in Rn, inscribed polygonal sums, arc length as their supremum, and rectifiability).

Proof

technique · two inequalities
1.1givenL1L2

Suppose first that φ is nondecreasing. The image under φ of any partition of [c,d] is a nondecreasing finite list from a to b; deleting repetitions produces a partition of [a,b] with the same polygonal sum for γ.

1.2givenL1choose

Conversely, for a partition a=t0<⋯<tm=b, choose one si∈φ−1(ti) for each of its finitely many values. Monotonicity forces s0<⋯<sm, after taking s0=c and sm=d, and the resulting polygonal sum of γ∘φ equals that of γ.

2.1step 1.1L2

Hence every polygonal sum of γ∘φ is at most L(γ), so L(γ∘φ)≤L(γ).

2.2step 1.2L2

Taking the supremum over target partitions gives L(γ)≤L(γ∘φ), proving equality in the nondecreasing case.

2.3step 1.1step 1.2L1L2

If φ is nonincreasing, reverse the order of every finite list in steps 1.1 and 1.2; Euclidean chord lengths are symmetric, so the same two inequalities hold.

3.1givenL2∎

If [c,d] is a singleton, so is its image [a,b], and the singleton convention in [L2] gives both lengths as zero. If instead a=b while c<d, then γ∘φ is constant, so every polygonal sum for it vanishes and L[c,d](γ∘φ)=0, while L[a,b](γ)=0 by the same convention.

Depends on

Dependency tree · 2 levels

Sources