TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28

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Associated primes commute with localization for finite modules

Statement

Let $R$ be a Noetherian commutative ring, let $M$ be a finitely generated left $R$ -module, and let $S \subseteq R$ be multiplicative. Then ${Ass}_{S^{- 1} R} (S^{- 1} M) = {S^{- 1} p : p \in {Ass}_{R} (M), p \cap S = \emptyset} .$

Facts & Assumptions

Given: A Noetherian commutative ring $R$ , a finitely generated left $R$ -module $M$ , and a multiplicative subset $S \subseteq R$ .

[L1]

Associated primes of $M$ disjoint from $S$ localize to associated primes of $S^{- 1} M$ (Associated primes localize forward).

[L2]

Every associated prime of $S^{- 1} M$ is the localization of an associated prime of $M$ disjoint from $S$ (Associated primes of a localized finite module come from upstairs).

Proof

technique · direct

1.1L1

If $p \in {Ass}_{R} (M)$ and $p \cap S = \emptyset$ , then [L1] gives $S^{- 1} p \in {Ass}_{S^{- 1} R} (S^{- 1} M)$ .

1.2L2

Conversely, if $q \in {Ass}_{S^{- 1} R} (S^{- 1} M)$ , then [L2] produces $p \in {Ass}_{R} (M)$ with $p \cap S = \emptyset$ and $q = S^{- 1} p$ .

Associated primes commute with localization for finite modules

Statement

Facts & Assumptions

Proof

Depends on

Dependency tree · 2 levels

Sources