TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedaudited 2026-09-22

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The Bessel inequality for an arbitrary orthonormal family

Statement

Let $(e_{i})_{i \in I}$ be an orthonormal family in a real or complex inner-product space $H$ (Orthonormal families, complete orthonormal systems and Hilbert bases). Then for every $x \in H$ the nonnegative family $(∣ ⟨ x, e_{i} ⟩ ∣^{2})_{i \in I}$ has finite sum in the finite-subset-supremum convention (Square-summable families on an arbitrary index set and the space $ℓ^{2} (I)$ ) and

$\sum_{i \in I} ∣ ⟨ x, e_{i} ⟩ ∣^{2} \leq ∥ x ∥^{2} .$

In particular the coefficient family $(⟨ x, e_{i} ⟩)_{i \in I}$ belongs to $ℓ^{2} (I, F)$ , and the inequality holds with no hypothesis on the cardinality of $I$ and with no completeness of $H$ .

Facts & Assumptions

[A1]

For every finite $F \subseteq I$ , $\sum_{i \in F} ∣ ⟨ x, e_{i} ⟩ ∣^{2} \leq ∥ x ∥^{2}$ ; the sum over the empty set is $0$ (The finite Bessel inequality and best approximation by a finite orthonormal family).

[A2]

The arbitrary sum $\sum_{i \in I} ∣ ⟨ x, e_{i} ⟩ ∣^{2}$ is the supremum in $[0, + \infty]$ of the finite subsums, and it is a real number exactly when that set of finite subsums is bounded above (Square-summable families on an arbitrary index set and the space $ℓ^{2} (I)$ ).

[A3]

$∥ x ∥^{2}$ is a nonnegative real number, and a family belongs to $ℓ^{2} (I, F)$ exactly when its square sum is finite (Square-summable families on an arbitrary index set and the space $ℓ^{2} (I)$ ).

Proof

technique · direct

Given: An orthonormal family $(e_{i})_{i \in I}$ in $H$ and a vector $x \in H$ .

1.1A1A3

Every finite $F \subseteq I$ satisfies $\sum_{i \in F} ∣ ⟨ x, e_{i} ⟩ ∣^{2} \leq ∥ x ∥^{2}$ , so the set of finite subsums of the family $(∣ ⟨ x, e_{i} ⟩ ∣^{2})_{i \in I}$ is nonempty and bounded above by the real number $∥ x ∥^{2}$ .

2.1step 1.1A2A3

Consequently the arbitrary sum $\sum_{i \in I} ∣ ⟨ x, e_{i} ⟩ ∣^{2}$ is a real number and is at most $∥ x ∥^{2}$ , being the supremum of a nonempty set of reals bounded above by $∥ x ∥^{2}$ .

3.1step 2.1A3∎

The value $\sum_{i \in I} ∣ ⟨ x, e_{i} ⟩ ∣^{2}$ is finite, so the coefficient family $(⟨ x, e_{i} ⟩)_{i \in I}$ lies in $ℓ^{2} (I, F)$ , and the Bessel inequality $\sum_{i \in I} ∣ ⟨ x, e_{i} ⟩ ∣^{2} \leq ∥ x ∥^{2}$ holds.

The Bessel inequality for an arbitrary orthonormal family

Statement

Facts & Assumptions

Proof

Depends on

Dependency tree · 2 levels

Sources