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Finite linear combinations of box indicators are dense in for
Statement
Assume the Axiom of Countable Choice.
Let . Finite linear combinations of indicator functions of boxes are dense in .
Facts & Assumptions
Given: The Axiom of Countable Choice, , , and .
Simple functions with finite-measure support are dense in (Simple functions with finite-measure support are dense in for ).
Every finite-measure measurable set can be approximated in symmetric difference by a finite union of boxes (A finite-measure measurable set in is approximable in measure by a finite union of boxes).
Minkowski's inequality is available in (Minkowski's inequality for integrals, including ).
Proof
By [L1], choose a simple function [L1, L2, given, choose] with each of finite measure and . For each , choose a finite union of boxes with by [L2].
Put [L3, step 1.1, algebra] Then by [L3] and the choice of the .
Therefore [step 1.1, step 2.1, algebra] Since is a finite linear combination of box indicators, these functions are dense in .