How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Two positivity bounds from Virasoro norm identities
Statement
Let be the Virasoro algebra with central element , represented by operators on an invariant complex inner-product space , with inner product conjugate-linear in the first variable and linear in the second. Assume , the form is positive definite, and for all vectors used below the adjoint identity holds. If is a highest-weight vector of weight (so for and ), then . If is a vacuum vector with for every , then . These are only the two norm inequalities; no classification of unitary Virasoro representations is asserted.
Facts & Assumptions
Given: A representation of the fixed Virasoro algebra on the invariant domain, a positive-definite inner product, the stated adjoint identities, and the highest-weight and vacuum vectors.
Virasoro algebra in the convention: , and is central.
Highest-weight vector and module for Virasoro: A highest-weight vector satisfies for all , , and ; the definition itself asserts neither unitarity nor irreducibility.
The operators preserve the common domain, the inner product is positive definite, and the adjoint relation is valid on and .
The vacuum vector is nonzero and obeys for every ; in particular .
Proof
Given: [F1]–[F2], [A1]–[A2], and the indicated vectors.
For the highest-weight vector, adjointness gives . Since , the operator product equals ; [F1] gives because . Hence .
For the vacuum, adjointness gives because . By [F1], on this representation; [A2] therefore gives .
The left side of step 1.1 is a nonnegative real number and . Therefore is real and nonnegative.
Positivity and make real and nonnegative. The two conclusions above give exactly the asserted bounds and no stronger representation-theoretic classification.