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Full harmonic Majumdar-Papapetrou Einstein-Maxwell verification

Statement

Every datum of Positive harmonic conformastatic electrovac data satisfies the source-free geometric Einstein-Maxwell equations of Geometric electrovac equations and flux normalization:

dFσ=0,d(⋆gFσ)=0,Ric⁡ab=2Qab(Fσ),Qab(F):=FacFbc−14gabFcdFcd.

More explicitly, with qH:=∑iHi2, the only nonzero independent raised field components are Fσi0=σHi/H2 and the quadratic-field components are

Fσ,abFσab=−2qHH4,Q00=qH2H6,Q0i=0,Qij=δijqH−2HiHj2H2.

Facts & Assumptions

Given: The data of Positive harmonic conformastatic electrovac data, its Lorentzian metric, and the geometric electrovac convention in Geometric electrovac equations and flux normalization.

[F1]

Positive harmonic conformastatic electrovac data supplies H>0, ΔδH=0, g00=−H−2, gij=H2δij, Aσ=σ(H−1−1)dx0, and Fi0=−σHi/H2.

[F2]

The positive-scalar conformastatic chart tensor is Lorentzian supplies g00=−H2, gij=H−2δij, ∣det⁡g∣=H2, and the future orthonormal frame n=H∂x0, ei=H−1∂i.

[F3]

Arbitrary-positive-H conformastatic Ricci and Einstein components states the curvature convention and gives Γ00i=−Hi/H, Γi00=−Hi/H5, and Γijk=(δijHk+δikHj−δjkHi)/H. Summing its coordinate Ricci formula gives Γααi=2Hi/H, Γαα0=0, and its arbitrary-positive-H Ricci table.

[F4]

Sourced Maxwell sign and current conservation proves d(⋆gF)=−ιvvolg for vb=∇aFab, so v=0 implies the source-free second Maxwell equation.

[F5]

Lorentzian exterior calculus and Hodge star supplies d2=0 for smooth differential forms.

[A1]

The hypotheses of Positive harmonic conformastatic electrovac data hold on D; in particular H is smooth, positive, time-independent, and Euclidean harmonic.

Proof

1.1givenF1F2F5algebra

Since Fσ=dAσ, the identity d2=0 in [F5] gives dFσ=0. Raising the two indices of Fi0=−σHi/H2 with [F2] gives Fi0=σHi/H2 and F0i=−σHi/H2. Contracting the antisymmetric pair yields FabFab=2∑iFi0Fi0=−2qH/H4.

2.1givenF1F2F3A1step 1.1algebra

The last Christoffel term in ∇aFab=∂aFab+ΓaacFcb+ΓbacFac vanishes because Γbac is symmetric in a,c and Fac is antisymmetric. For b=0, the remaining terms are ∂i(σHi/H2)+(2Hi/H)(σHi/H2)=σΔδH/H2=0, after the product rule cancels the two qH/H3 terms. For b=i, ∂0F0i=0, all Fji=0, and the only possible trace term is Γαα0F0i=0. Thus vb=∇aFab=0 for every b, and [F4] gives d(⋆gFσ)=0.

2.2givenF1F2step 1.1algebra

The only nonzero contraction in F0cF0c is ∑iF0iF0i=qH/H6, while FicFjc=Fi0g00Fj0=−HiHj/H2. Combining these with FabFab=−2qH/H4 and g00=−H−2, gij=H2δij gives Q00=qH/(2H6), Q0i=0, and Qij=(δijqH−2HiHj)/(2H2).

3.1givenF2F3step 1.1step 2.1step 2.2algebra∎

Substituting ΔδH=0 into the arbitrary-positive-H table [F3] gives Ric⁡00=qH/H6, Ric⁡0i=0, and Ric⁡ij=(δijqH−2HiHj)/H2. These are exactly twice the entries in step 2.2; together with the closedness in step 1.1 and source-free divergence in step 2.1 they are all three equations in Geometric electrovac equations and flux normalization.

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